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VladimirAG [237]
3 years ago
13

You move a 25 N object 5 meters. If it takes 8 s how much power did you do?

Physics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

15.625 watts

Explanation:

Recall that power is defined as the worked performed per unit of time:

Power = Work / time

The work done is Force * distance, so in our case the work is:

Work = 25 M * 5 m = 125 J

Then the power will be:

Power = 125 J / 8 sec = 15.625 watts

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Nitrogen gas (N2) and hydrogen gas (H2) combine to form ammonia (NH3). Which equation correctly represents this reaction?
sweet [91]

Answer:

The correctly equation is D) N2+ 3H2 → 2NH3

Explanation:

Both nitrogen and hydrogen are presented in bimolecular form (N2 and H2), on one side and on the other side of the equation we have 2 Nitrogens and 6 Hydrogens (it is balanced)

5 0
4 years ago
a body starts from rest and moving under uniform acceleration of 4 metre per second square travel half of its total path during
lakkis [162]

Answer:

t = 3.414 s

s = 23.3 m

Explanation:

Let t be the total time of motion

Let s be the total distance of motion

s - s/2 = ½at² - ½a(t - 1²) = ½a(t² - (t - 1)²)

s/2 = ½a(t² - (t² - 2t + 1)) = ½a(t² - t² + 2t - 1)

s = a(2t - 1)

s = 4(2t - 1)

s = 8t - 4

8t - 4 = ½4t²

8t - 4 = 2t²

0 = 2t² - 8t + 4

0 = t² - 4t + 2

t = (4 ±√(4² - 4(1)(2))) / 2 = (4 ± √8)/2 = 2 ± √2

t = 3.414 s

or

t = 0.5857... s which we ignore because it does not have a full last second.

s = ½(4)3.414² = 23.3137... 23.3 m

5 0
3 years ago
When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Bezzdna [24]

Answer:

Distance between the charges, r = 0.8 meters

Explanation:

Given that,

Charge 1, q_1=+8.4\ \mu C=+8.4\times 10^{-6}\ C

Charge 2, q_2=+5.6\ \mu C=+5.6\times 10^{-6}\ C

Repulsive force between charges, F = 0.66 N

Let r is the distance between charges. The formula for the electrostatic force is given by :

F=k\dfrac{q_1q_2}{r^2}

r=\sqrt{\dfrac{kq_1q_2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times 8.4\times 10^{-6}\times 5.6\times 10^{-6}}{0.66}}

r = 0.8009 meters

or

r = 0.8 meters

So, the distance between the charges i 0.8 meters. Hence, this is the required solution.

4 0
3 years ago
What two aspects of a force do scientists measure?
malfutka [58]
_Award brainliest if helped!
Force is a vector, A. Magnitude and Direction. 
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