Answer:
D
Explanation:
correct me if I'm wrong on your answer and it's the right answer from my son
Answer:
A baseball (m= 149g) approaches a bat horizontally at a speed of 40.2 m/s (90 mi/h) and is hit straight back at a speed of 45.6m/s (102mi/h). If the ball is in contact with the bat for a time of 1.10ms, what is the average force exerted on the ball by the bat ? Neglect the weight of the ball, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.
Explanation:
Use the impulse equation (a form of Newton's 2nd Law): FΔt = Δ(mv) where Δ means "change in"
The change in momentum is mBB(vf - vi) = (.150 kg)(-46.9 m/s - 40.5 m/s)
Divide this by the time interval and you get F exerted by the bat in Newtons.
Take care.
Momentum = mass x velocity
m=7.3kg
v=20 m/s
momentum= 7.3(20) = 146 kg m/s
<span>¿Qué estás pidiendo en esta situación. Hay entornos de diferencia de los animales. Algunos viven en entornos de tundra, otra veraniega en vivo, ambientes cálidos.</span>
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