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Luba_88 [7]
3 years ago
11

The strength of an electric field depends on the

Physics
2 answers:
Maksim231197 [3]3 years ago
7 0
Electric field is directly proportional to the product of both the charges and inversely proportional to the square of distance between them. So, it depends on both, magnitude of charges, and the distance between them

In short, Your Answer would be Option D

Hope this helps!
Snowcat [4.5K]3 years ago
4 0

Answer: The correct answer is " amount of charge on a test charge placed in the field."

Explanation:

The expression of the electric field at a distance from the source charge is as follows;

E=\frac{kq}{r^{2} }

Here, q is the charge, E is the electric field, k is constant and r is the distance from the charge.

The electric field and the distance have an inverse relation. It varies inversely as the square of the distance. The electric field is directly proportional to the charge.

The strength of the electric field increases with decrease in the distance from the charge. From the given options, the options (a) and (b) are correct. The electric field depends on the distance from the charge and the amount of charge that produces the electric field.

Therefore, the correct option is (d).

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A hot–air balloon is moving at a speed of 10.0 meters/second in the +x–direction. The balloonist throws a brass ball in the +x–d
yulyashka [42]

Option (D) is correct.

The balloon lands horizontally at a distance of 420 m from a point where it as released.

Explanation:

Velocity of air balloon along +X axis =10 m/s

velocity of ball=4 m/s along + X axis

the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s

time taken= 30 s

The distance traveled is given by d= v t

d= 14 (30)

d= 420 m

Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.

3 0
3 years ago
Two positive point charges are 4.9cm apart. If the electric potential energy is 70.0 μJ, what is the magnitude of the force betw
ExtremeBDS [4]

Hi there!

Recall the following:

V \text{ (Electric Potential Energy) } = \frac{kq_1q_2}{r}\\\\F_E = \frac{kq_1q_2}{r^2}

k = Coulomb's Constant (Jm/C²)

q = Charge (C)
r = distance between charges (m)

To calculate the electric force between the two charges, we can simply divide by another 'r' (distance):

F_E = \frac{70}{0.049} = \boxed{1428.57 \mu J}

6 0
2 years ago
Find the specific gravity of the rose quartz. Specific gravity = density of of water.
Veronika [31]
It has no units. not sure.
6 0
3 years ago
The diameter of a hydrogen atom is 0.000000000106 m. How can this
Andreas93 [3]

Answer:

The diameter of a hydrogen atom based on scientific notation is 1.06 x 10^-10 m

8 0
3 years ago
Plss help me fast and finish all directions. Correct Drawing/picture plss. Make sure the drawing is clear so I can snip it and p
jeka94

Answer:

Ive left an image here for use, I hope its helpful

Explanation:

I have left two images and i hope i am answering your question.

5 0
3 years ago
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