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IceJOKER [234]
2 years ago
7

Which equation could he have solved? Is it A or B

Mathematics
1 answer:
Artist 52 [7]2 years ago
7 0
A or B ....it’s your choice
You might be interested in
75
Vinvika [58]

Answer:

B. 210°

hope it helps

have a nice day

8 0
3 years ago
Rodger has 47 cars . Can he group the cars in more than two ways?
deff fn [24]
First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest
4 0
2 years ago
the circle below has center T. suppose that m UV = 138 degrees and that UW is tangent to the circle at U. find the following
alisha [4.7K]

Angle UTV is basically given: it's 138°.

Moreover, since UTV is isosceles, the other two angles have the same measure x. We thus have

138+x+x=180 \iff 2x=42 \iff x=21

So, TUV is 21°, and VUW is complementary, so it must be 69° so that they sum up to 90°

3 0
3 years ago
The formula to find the period of orbit of a satellite around a planet is T2=(4π2GM)r3 where r is the orbit’s mean radius, M is
tatyana61 [14]
I know what is the answer to this problem, I believe, if you cannot do it on your own check out www.answers.yahoo.com or private message me so I can explain
7 0
3 years ago
A shipment of 10 computers contains 2 with defects. Find the probability that a sample of size 2​, drawn from the ​10, will not
Mrrafil [7]

Answer:

\frac{28}{45} .

Step-by-step explanation:

way_1:

according to the condition the probability for the 1st computer is 8/10=4/5;

for the 2d computer is 7/9. Then the final probability is P=4/5 * 7/9=28/45;

way_2:

the required probability can be calculated according the formula:

P=\frac{no-cases}{total-cases};

then

P=\frac{C^2_8}{C^2_{10}} =\frac{2!8!8!}{2!6!10!}=\frac{28}{45} .

8 0
1 year ago
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