The experimental research has two key advantages over correlational studies.
1. The possibility of random assignment
2. Causal connections can be assumed.
<h3>
What benefit does experimental research have over correlational research?</h3>
Correlational studies merely examine the data that already exists, whereas experimental studies give the researcher the opportunity to influence the study's factors. Researchers can make inferences about how changes in one variable affect changes in another through the use of experimental investigations.
The factors in a correlation study are out of the control of the researcher or research team. The researcher merely measures the information she discovers in the outside world. She can then determine whether changes in one are related to changes in the other, or if the two variables are correlated. In such a study, experimenters gather existing data and use statistical methods to examine it, such as economic statistics from governments. The findings of correlation studies can lead to hypotheses that can be verified through a more focused experimental one.
To learn more about correlational research visit:
brainly.com/question/14375687
#SPJ4
Answer:
27.5
Step-by-step explanation:
1.5(5)+20=27.5
:) hope its right :)
1) The scenario is represented by the equation 1/8(x+16)=76/8, where x is the food bill.
2) The total food bill is represented by the equation x=60.
Both of these responses are correct.
Step-by-step instructions:
Because there are eight buddies in the group, the total money spent by them is $76 (including the $16 tip).
Our equation can be as follows if x is the food bill:
76/8 = (x+16)/8
Solving the Problem
9.5 = (x+16)/8
9.5*8 Equals x+16
x=76 -16 x=76 -16 x=76 -16 x=
60 = x
The cost of food is x=60.
Answer:
B
Step-by-step explanation:
y-intercept is positive 5 so that eliminates answer choices A and C
to decide between B and D, select a point in the solution area; for example, (0, 0). Plug these values into B and D and see which one it is true for
B) 0 ≥ -3(0)-5
Is 0 ≥ -5 Yes
D) 0 ≤ -3(0)-5
Is 0 ≤ -5 No
