Please help I asked this question earlier and nobody answered! :(

Mathematics

1 answer:

tatiyna3 years ago

8 0

Answer:

Step-by-step explanation:

One way to tell is to put both equations into slope-intercept form. That form is usually written $y=mx+b$ where m is the slope and b is the y-intercept.

Solve the first equation for y.

$6x+2y=5 \\ 2y=-6x+5 \\ y=-3x+5/2$

The slope of this line is -3, and its y-intercept is 5/2.

Solve the second equation for y.

$y+3x=2\\y=-3x+2$

The slope of this line is -3 and its y-intercept is 2.

The lines are parallel because they have the same slope and different y-intercepts. There is no solution to the system.

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Write the equation of a line that is perpendicular to the given line and that passes through the given point.

HACTEHA [7]

First, let's re-arrange to slope-intercept form.

x + 8y = 27

Subtract 'x' to both sides:

8y = -x + 27

Divide 8 to both sides:

y = -1/8x + 3.375

So the slope of this line is -1/8, to find the slope that is perpendicular to this, we multiply it by -1 and flip it. -1/8 * -1 = 1/8, flipping it will give us 8/1 or 8.

So the slope of the perpendicular line will be 8.

Now we can plug this into point-slope form along with the point given.

y - y1 = m(x - x1)

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Me ajudem com a 3º questão

Alisiya [41]

I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.

$10 = \dfrac{n(n-3)}{2}$