Answer:
3
Step-by-step explanation:
subtract 1 from 13 divide the number by 4
Answer:
1.2x10^-11
You never start with a zero so you move the decimal 11 spots the right which makes it negative
the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
Answer:
Step-by-step explanation:
Remark
Area of an entire circle = pi * r^2
Area of a sector = angle / 360 * pi * r^2
Givens
angle = 140
radius = 8
Solution
Area = (140/360) * 3.14 * 8^2
Area =0.3889 * 3.14 * 64
Area = 78.15