Answer:
The larger number is 64 and the smaller number is 36.
Step-by-step explanation:
Set up an equation to find the value of one number, x, and use that find find the value of the second number. Use x as the variable for the smaller number. The larger number is 2 times the smaller number minus 8, so the part of the equation for the larger number would be 2x-8. Then because the difference between the two numbers is 28, you would subtract the smaller number, x, from the larger number equation.
The equation should look like this: 2x-8-x=28
Combine like terms to get this: x-8=28
Add 8 to both sides of the equation: x=36
Because x represents the smaller number, the smaller number is 36. To find the larger number, just plug the numbers into the large number equation from earlier: 2(36)-8 The answer for the large number is 64, and the difference between 64 and 36 is 28, proving the answer correct.
Answer: X= John's age , Y= Fernando's age, Z = Age of Luis uncle
Step-by-step explanation:
Given: John is 20 years younger than fernando.
i.e. John' age + 20 = Fernando's age
So in the given equation "X+20=Y " , X= John's age and Y= Fernando's age.
From this , John's age: X= Y-20 (i)
Also, Luis uncle is 3 years younger than his dad( John).
Age of Luis uncle = John's age -3
=X-3
= Y-20-3 [From i]
So in the given equation Y-20-3=Z , Z = Age of Luis uncle
Step-by-step explanation:
Given the information:
- 1st square: 12 square units
- 2nd square: DOUBLE that of the first square = 2*12 = 24 square units
From that, we can determine the length of the side in each square:
1/ ![x^{2} = 12](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D%2012)
<=> x = 2
2/ ![a^{2} = 24](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%3D%2024)
<=> a = 2
Please have a look at the attached photo.
Hope it will find you well.
Answer:
x = 25
Step-by-step explanation:
Given
0.2(x + 5) + 1 = 7 ( subtract 1 from both sides )
0.2(x + 5) = 6 ( divide both sides by 0.2 )
x + 5 = 30 ( subtract 5 from both sides )
x = 25
Answer
g(x) = e^ (x)^1/2
Derivate with respect to x
g'(x) = (1/2 -1)*x^(1/2 -1) * e^ (x)^1/2
g'(x) = (-1/2)*x^(-1/2) * e^ (x)^1/2