The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial 
has solutions 
, then you can factor it as
So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as
But this is a fourth-degree polynomial.
Answer:
Y = 5
X= 6
Step-by-step explanation:
I just solved it by my mind you just check it
Answer:
Step-by-step explanation:
Let d represent the number of dimes. Then the number of quarters is 2d-3 and the total value of the coins is ...
0.10d + 0.25(2d-3) = 7.05
0.60d -0.75 = 7.05 . . . . . . . simplify
d = (7.05 +0.75)/0.60 = 13 . . . . add 0.75, divide by 0.60
2d-3 = 2·13 -3 = 23
Brandon has 23 quarters and 13 dimes.
Answer:
=
$
518.01
Explanation:
compound interest formula $A = P*(1+R)^n#
P
=
$
400
,
r
=
.09
,
n
=
3
Substituting the values, we get A =
400
⋅
(
1.09
)
3
=
$
518.01
From my alt account from, https://socratic.org/questions/how-much-would-400-invested-at-9-interest-compounded-continuously-be-worth-after
Yes, on the left side you are adding 3x+2 in one and 2+3x in the other. these add to the same number because addition is Commutative on the real numbers.
