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Inga [223]
3 years ago
11

3xy^3 + 5- x- 2xy^3= xy^3 +11 Solve please

Mathematics
2 answers:
snow_lady [41]3 years ago
8 0

Answer:


Step-by-step explanation: 3XY 3+5-X-2XY3=XY3+11  USE THE COMMUTATIVE PROPERTY TO REODER THE TERMS...3Y3+5-X-2XY3=XY3+11 COLLECT LIKE TERMS Y3+5-X-Y3X+11..Cancel equal terms on both sides of the equation 5-x=11 move constant to the right side and change its sign  -x=11-5 subtract the numbers -x=6 final answer is X=-6


sergey [27]3 years ago
8 0
Hope you can read this. I didnt wanna make a blocky chunk of text with all the exponents so I handwrote it :)

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wel
Lilly should re-estimate the original numbers to be smaller.
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4 0
3 years ago
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3 years ago
15. Explain why we need to specify 0 < b < 1 and b > 1 as valid values for the base b in the expression logb(xx).
damaskus [11]

Answer:

The base (b) has to be positive and different of 1. The logarithm is the inverse of exponential, so:

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For b = 1 ⇒ 1ˣ = a

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3 0
3 years ago
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Answer:

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4 0
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Step-by-step explanation:

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3 years ago
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