Ask question

Ask question

All categories

3 years ago

12

What are the two values on a number line that are a distance of 5 from 0?

1 answer:

dusya [7]3 years ago

4 0

Answer:

<h3>5 and -5</h3>

Step-by-step explanation:

For a number line the centre of the line is the origin (0, 0). To get the two numbers that are a distance of 5 from 0, we will add 5 to 0 and subtract 5 from 0.

Towards the positive x axis;

The value at a distance of 5 from 0 = 5- 0 = 5

Towards the negative x axis;

The value at a distance of 5 from 0 = -5- 0 = -5

Hence the two values on a number line that are a distance of 5 from 0 are 5 and -5

You might be interested in

HELP! Whoever gets it right gets brainliest!!

aleksandrvk [35]

Answer:

D infitently Many

Step-by-step explanation:

A system of linear equations usually has a single solution, but sometimes it can have no solution (parallel lines) or infinite solutions (same line). This article reviews all three cases. One solution. A system of linear equations has one solution when the graphs intersect at a point.

6 0

3 years ago

Maslowich

Answer: x = -2

<u>Step-by-step explanation:</u>

vertical line means it will be x = ___

Set the x-values equal to each other and solve for x.

3 - 2x = x + 9

<u> +2x</u> <u>+2x </u>

3 = 3x + 9

<u>-9 </u> <u> -9 </u>

-6 =3x

$\frac{-6}{3} = \frac{3x}{3}$

-2 = x

4 0

3 years ago

Read 2 more answers

Find the distance between the points (-1,-5) and (-10,7).

Paladinen [302]

Answer:

15 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (- 1, - 5) and (x₂, y₂ ) = (- 10, 7)

d = $\sqrt{(-10+1)^2+(7+5)^2}$

= $\sqrt{(-9)^2+12^2}$

= $\sqrt{81+144}$

= $\sqrt{225}$

= 15 units

5 0

3 years ago

What is an equation of the line that passes through the point (3,6)(3,6) and is parallel to the line 4x-3y=214x−3y=21?

polet [3.4K]

<em><u>Question:</u></em>

What is an equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>Answer:</u></em>

<em><u>The equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21 is:</u></em>

$y = \frac{4}{3}x + 2$

<em><u>Solution:</u></em>

Given that line passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------- eqn 1

Where, "m" is the slope and "c" is the y intercept

<em><u>Given equation is:</u></em>

4x - 3y = 21

Rearrange,

3y = 4x - 21

$y = \frac{4}{3}x - \frac{21}{3}\\\\y = \frac{4}{3}x - 7$

On comparing above equation with eqn 1,

$m = \frac{4}{3}$

We know that slopes of parallel lines are same

Therefore, slope of line parallel to the line 4x - 3y = 21 is 4/3

<em><u>Substitute m = 4/3 and (x, y) = (3, 6) in eqn 1</u></em>

$6 = \frac{4}{3} \times 3 + c\\\\6 = 4 + c\\\\c = 2$

<em><u>Substitute c = 2 and m = 4/3 in eqn 1</u></em>

$y = \frac{4}{3}x + 2$

Thus the equation of line is found

4 0

4 years ago

How many unique triangles can be made with 3,5,8

blondinia [14]

Answer

2 or 3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers