Answer:
Anita 's power rating during this portion of the climb is 1568 Watts.
Explanation:
Given that,
Mass of the body, m = 800 kg
Height, h = 20 m
Time, t = 100 s
We need to find the Anita 's power rating during this portion of the climb. Power rating of an object is given by the work done per unit time. It is given by :
P = 1568 Watts
So, Anita 's power rating during this portion of the climb is 1568 Watts. Hence, this is the required solution.
Answer: GREATER
Explanation:when elevator does not move it reads weight of the person . when elevator moves up let apparent weight be F . W acts downwards so net force is F-W
HENCE
F-W =ma
F= ma+W
AS a= 1 m/s^2
F = m (1)+W
HENCE GREATER
Explanation:
The specific heat capacity is the heat or energy required to change one unit mass of a substance of a constant volume by 1 °C. The formula is Cv = Q / (ΔT ⨉ m) .
Answer:
Explanation:
Speed of car =22.5miles/hr
U=22.5miles/hour
Applied brake and come to rest
Final velocity, =0
t, =2sec
Given that,
Speed=distance /time
Then,
Distance, =speed, ×time
Converting mile/hour to m/s
Given that
Use: 1 mile= 1600 m, 1 h= 3600s
22.5miles/hour × 1600m/mile × 1hour/3600s
Therefore, 22.5mile/hour=10m/s
Using speed =10m/s
Distance =speed ×time
Distance=10×2
Distance, =20m
The distance travelled before coming to rest is 20m.
- Initial velocity,u = -2 m/s
- Final velocity,v = -10 m/s
- Time taken, t = 4 seconds
Find the acceleration ( a ) .
We know that,
Substituting the values in the above formula, we get
Hence,the acceleration of a body is -2 m/s².
