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Rom4ik [11]
3 years ago
6

You are walking on a beach and see a split. Explain how a split could have formed from a rocky headland.

Chemistry
2 answers:
kirza4 [7]3 years ago
8 0

Hello, Lindaparker, a spit  could form from a rocky headland where prevailing winds would blow at an angle to the rocky headland, gradually depositing sand and shingle at that place. A spit is a permanent land form resulting from marine deposition and wind deposition. It is usually a long and narrow accumulation of sand or shingle with one joined to the land and the other end projecting at   a narrow angle out into the sea. Salt marshes sometimes form on the sheltered side of a spit.

Natasha_Volkova [10]3 years ago
5 0
It could have been something to do with the rocky headland rubbing against the split. Just guessing though.
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The internet is a local communication network that allows only certain computers to connect and exchange information True or fal
choli [55]
False, the internet branches throughout many countries connecting you to the rest of the world from home. Hope it helped!
6 0
3 years ago
A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the
Sveta_85 [38]

Answer:

The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL

Explanation:

Using the formula

Ca Va = Cb Vb

Cb = 0.32 M

Vb = 50 mL = 50/1000 = 0.050L

Ca = 0.5 M

Va =?

Substituting for Va in the equation, we obtain:

Va = Cb Vb / Ca

Va = 0.32 * 0.05 / 0.5

Va = 0.016 / 0.5

Va = 0.032 L

The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL

6 0
3 years ago
HELP HELP HELP HOW MANY GRAMS OF SUGAR CAN DISSOLVE IN 100 GRAMS OF WATER HEATED TO 40 CELCIOUS 60 POINTS OFFERED
Colt1911 [192]

your answer would be C. 240g

3 0
3 years ago
Carbondioxide gas is't collectable in water. why​?
Lisa [10]

Answer:

carbon dioxide is a gas so it isn't collected over water.

Explanation:

it works for insoluble gases such as hydrogen,or gases that do not dissolve easily in water such as ammonia and chlorine are readily soluble in water and are not collected this way.

hope it is helpful for you.

4 0
3 years ago
6. What is the oxidation number for the atom indicated in the following compounds.
Hatshy [7]

Answer:

a. +6;

b. +5;

c. +3.

Explanation:

Start with elements with well-known oxidation states.

The oxidation state on oxygen O in compounds is mostly -2. Common exceptions include:

  • -1 in peroxides and
  • positive when oxygen bonds to fluorine.

The oxidation state on group 1 metals (Li, Na, K, etc.) in compounds is mostly +1.

The oxidation state on group 2 metals (Be, Mg, Ca, etc.) in compounds is mostly +2.

Barium Ba is a group 2 metal. The oxidation state on Ba in the compound BaSO₄ is expected to be +2.

The oxidation state on hydrogen H in compounds is mostly +1. The oxidation state on H might be negative when it is bonded to metals.  

The oxidation state on halogens (F, Cl, Br, etc.) is mostly -1. The oxidation state may vary when the halogen is bonded to oxygen or another halogen element.

Compounds are neutral. The oxidation state on all atoms in a compound shall add up to 0. Both BaSO₄ and HClO₂ are neutral.

<h3>BaSO₄</h3>

Oxidation states:

  • Ba: +2;
  • The oxidation state on sulfur S is to be determined;
  • O: -2.

Let the oxidation state on S be x.

2 + x + 4 × (-2) = 0;

x = 6.

Hence, the oxidation state on S in BaSO₄ is +6.

<h3>HClO₂</h3>

Oxidation states:

  • H: +1;
  • Cl here is bonded to oxygen. The oxidation state on chlorine Cl is to be determined;
  • O: -2.

Let the oxidation state on Cl be x.

<em>Refer to the equation in BaSO₄ as an example. Try setting up the equation on your own. </em>

x = 3.

Hence, the oxidation state on Cl is +3.

<h3>PO₄³⁻</h3>

Ions carry charge. Oxidation states on atoms in an ion shall add up to the charge of the ion. The superscript of an ion shows its charge. The superscript 3- in the phosphate ion shows that the ion carries a charge of -3.

Oxidation states:

  • The oxidation state on P is to be found;
  • O: -2.

Let the oxidation state on P be x.

x + 4 × (-2) = -3;

x = 5.

Hence, the oxidation state on P is +5.

4 0
3 years ago
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