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2 years ago

Which of the following two conditions will favor a spontaneous reaction?

Chemistry

1 answer:

Alexxx [7]2 years ago

8 0

Answer:

option A

an increase in entropy and a decrease in enthalpy

pls mark brainliest

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Why foodstuff with acid components should not be stored in aluminium containers why?

adell [148]

Answer:

Hey dear, foodstuff with acid components should not be stored in aluminum utensils because Aluminum is one of the most reactive metal which can easily react with acid to form toxic substances which can effect our health .

HOPE THIS HELPED!!!!!!XDDD

6 0

3 years ago

Written in this form, carbon-13, what does the 13 represent and what is the atomic number?

tigry1 [53]

Explanation:
Carbon has 3 isotopes. Carbon-12, Carbon-13, and Carbon-14
All of them have an atomic number of 6, which means all of them have 6 protons (if they had different numbers of protons, they'd be different elements).
Since they all have 6 protons, in their elemental forms, they all have 6 electrons, too.
Carbon-12:
Atomic number: 6
Mass number: 12
protons: 6
electrons: 6
neutrons: 6
Carbon-13:
Atomic number: 6
Mass number: 13
protons: 6
electrons: 6
neutrons: 7
Carbon-14:
Atomic number: 6
Mass number: 14
protons: 6
electrons: 6
neutrons: 8

8 0

2 years ago

How many mm are in 38,987 L?

OlgaM077 [116]

Answer:

38987000

Explanation:

there are 1000 ml in a Liter.

Hope this helps!

6 0

2 years ago

An alien civilization has different names and symbols for six elements. Place each element in the correct location in the period

Margarita [4]

Answer:

why whould I know that!!??

Explanation:

3 0

2 years ago

Read 2 more answers

Aluminum reacts with sulfur gas to produce aluminum sulfide. a) What is the limiting reactant? What is the excess reagent? b) Ho

Sophie [7]

Answer:

a) Limiting: sulfur. Excess: aluminium.

b) 1.56g Al₂S₃.

c) 0.72g Al

Explanation:

Hello,

In this case, the initial mass of both aluminium and sulfur are missing, therefore, one could assume they are 1.00 g for each one. Thus, by considering the undergoing chemical reaction turns out:

$2Al(s)+3S_2(g)\rightarrow 2Al_2S_3(s)\\$

a) Thus, considering the assumed mass (which could be changed based on the one you are given), the limiting reagent is identified as shown below:

$n_S^{available}=1.00gS_2*\frac{1molS_2}{64gS_2} =0.0156molS_2\\n_S^{consumed\ by \ Al}=1.00gAl*\frac{1molAl}{27gAl}*\frac{3molS_2}{2molAl}=0.0556molS_2$

Thereby, since there 1.00g of aluminium will consume 0.0554 mol of sulfur but there are just 0.0156 mol available, the limiting reagent is sulfur and the excess reagent is aluminium.

b) By stoichiometry, the produced grams of aluminium sulfide are:

$m_{Al_2S_3}=0.0156molS_2*\frac{2molAl_2S_3}{3molS_2} *\frac{150gAl_2S_3}{1molAl_2S_3} =1.56gAl_2S_3$

c) The leftover is computed as follows:

$m_{Al}^{excess}=(0.0556-0.0156)molS_2*\frac{2molAl}{3molS_2}*\frac{27gAl}{1molAl} =0.72 gAl\\$

NOTE: Remember I assumed the quantities, they could change based on those you are given, so the results might be different, but the procedure is quite the same.

Best regards.

7 0

2 years ago