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aleksklad [387]
3 years ago
10

Find degree measures of marked angles in fig 5.47​

Mathematics
1 answer:
Sati [7]3 years ago
8 0

Answer:

50+P=125 exterior angle of the triangle is equal to the sum of two opposite interior angle

P=125-50=<em><u>7</u></em><em><u>5</u></em><em><u>°</u></em>

q+125=180 linear pair

q=180-125=<em>5</em><em>5</em><em>°</em>

<em>r</em><em>=</em><em>q</em><em>=</em><em>5</em><em>5</em><em>°</em><em> </em><em>vertically</em><em> </em><em>opposite</em><em> </em><em>angle</em>

s+85=125 exterior angle of the triangle is equal to the sum of two opposite interior angle

s=125-85=<em><u>4</u></em><em><u>0</u></em><em><u>°</u></em>

s+t=180 linear pair

t=180-40=<em><u>1</u></em><em><u>4</u></em><em><u>0</u></em><em><u>°</u></em>

u=s=<em><u>4</u></em><em><u>0</u></em><em><u>°</u></em><em><u> </u></em><em><u>vertically opposite angle</u></em>

w=<em><u>6</u></em><em><u>5</u></em><em><u>°</u></em><em><u> </u></em><em><u>vertically opposite </u></em><em><u>angle</u></em>

<em><u>v</u></em><em><u>+</u></em><em><u>u</u></em><em><u>+</u></em><em><u>w</u></em><em><u>=</u></em><em><u>1</u></em><em><u>8</u></em><em><u>0</u></em><em><u> </u></em><em><u>s</u></em><em><u>u</u></em><em><u>m</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>interior</u></em><em><u> </u></em><em><u>angle</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>1</u></em><em><u>8</u></em><em><u>0</u></em>

v+40+65=180

v=180-105=<em><u>7</u></em><em><u>5</u></em><em><u>°</u></em>

x+65=180 linear pair

x=180-65=<em><u>1</u></em><em><u>1</u></em><em><u>5</u></em><em><u>°</u></em>

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