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VMariaS [17]
3 years ago
6

Jack leaves from school and goes 4 miles north and 3 miles east to reach his home. How far is his home from school?

Mathematics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

  • D. 5 miles

Step-by-step explanation:

Jack forms a right triangle with his route: the distance between the school and home is the hypotenuse.

<u>It is equal to:</u>

  • √4²+3²= √25 = 5 miles

Correct choice is D

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In a sale all prices are reduced by 10% .What is the sale price of an article marked AED 75.
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67.5

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3 years ago
The length of the base of a triangle is twice its height. if the area of the triangle is 44 square​ kilometers, find the height
xeze [42]
Let
x
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Formular for area of Triangle
= ½ × base × height






thus,
{ \frac{1}{2} }(2x)(x)=44\ kilometers^2

Simplifying
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3 0
3 years ago
The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ &amp; Johnson​ (JNJ) stock for
egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
  • The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

4 0
3 years ago
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