A plane can fly 1020 miles in the same time as it takes a car to go 360 miles. If the car travels 110 mph slower than the plane,
1 answer:
Answer:
170 mph
Step-by-step explanation:
Let x mph be the plane's speed.
If the car travels 110 mph slower than the plane, then the car's speed is x - 110 mph.
<u>Plane:</u>
Speed = x mph
Distance = 1,020 miles
Time = t hours
<u>Car:</u>
Speed = x - 110 mph
Distance = 360 miles
Time = t hours
A plane can fly 1020 miles in the same time as it takes a car to go 360 miles, so
Cross multiply:
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Answer:
The correct option is (A).
Step-by-step explanation:
Let <em>X</em> = number of orange milk chocolate M&M’s.
The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.
The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.
The event of an milk chocolate M&M being orange is independent of the other candies.
The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.
The expected value of a Binomial random variable is:
Compute the expected number of orange milk chocolate M&M’s in a bag of 55 candies as follows:
It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.
This proportion is not surprising.
This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.
All unusual events have a very low probability, i.e. less than 0.05.
Compute the probability of P (X ≥ 14) as follows:
The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.
This probability is quite larger than 0.05.
Thus, the correct option is (A).