Write a proof that shows how 45 and 4.5 have a factor of 10. and are similar.
1 answer:
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Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× + 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = × 100
% change in stopping distance = 7.34 %