Answer:
From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km
So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr
So runner towards the west will be
distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8
So equating east and west time we have
x/9= (11-x)/8
8x=99-9x
17x=99
x=5.92 km
That is the distance covered by runner towards the east and he will meet the runner toward the west at
6-5.92=0.08 km west of the flagpole.
Answer:
2,500,000 MJ (
)
Explanation:
According to the work-energy theorem:
The work done on an object is equal to the amount of energy transferred
In this problem, the energy transferred by the rocket is

Therefore, the work done must be equal to the energy transferred, therefore:

Explanation:
wait I will give it ur answer
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