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3 years ago

Help please physics!!!

Physics

2 answers:

Hitman42 [59]3 years ago

6 0

Answer:

I think c is the answer.....

IRISSAK [1]3 years ago

5 0

Answer:

D, because weight is dragging the object down. C would be friction holding the object back, and A would be the momentum generated by the person pushing the object.

Explanation:

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andrezito [222]

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6 0

3 years ago

Name four type of friction and give one example for each

Sav [38]

Rolling friction ex. Riding a bike or skateboard
Sliding friction ex. Cartilage against your bone.
Fluid friction ex. Rowing a boat through the water.
Static friction ex. Trying to push a heavy object/ furniture

8 0

3 years ago

Read 2 more answers

A 0.280-kg volleyball approaches a player horizontally with a speed of 15.0 m/s. The player strikes the ball with her fist and c

Genrish500 [490]

Answer:

Impulse = 10.36 kg m/s

average force = 172.667 N

Explanation:

given data

mass = 0.280 kg

speed = 15.0 m/s

speed = 22.0 m/s

to find out

impulse and magnitude of the average force

solution

we know that Impulse is change in momentum that is

initial momentum = mass × speed ..........1

initial momentum = 0.28 × (15)

initial momentum = 4.2 kg m/s

Final momentum = mass × speed ..........2

Final momentum = 0.28 × (-22)

Final momentum = -6.16 kg m/s

so now we get Impulse that is

Impulse = 4.2 - (-6.16)

Impulse = 10.36 kg m/s

and

average force will be

average force = impulse ÷ time

average force = $\frac{10.36}{0.060}$

average force = 172.667 N

6 0

3 years ago

You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo

S_A_V [24]

Answer:

A. Z = 185.87Ω

B. I = 0.16A

C. V = 1mV

D. VL = 68.8V

E. Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

$Z=\sqrt{R^2+\omega^2L^2}$ (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

$Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega$

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

$I=\frac{V}{Z}$ (2)

V: voltage amplitude = 30.0V

$I=\frac{30.0V}{185.87\Omega}=0.16A$

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

$V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV$ (3)

D. The voltage across the inductor is:

$V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V$

E. The phase difference is given by:

$\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°$

5 0

3 years ago

The power ratings of several motors are listed in the table. A 2 column table with 3 rows. The first column is labeled motor wit

Lapatulllka [165]

The statement " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

Advertisement Rules:

An advertiser can not compare its products using the other companies name.

An advertiser can not make the false statement in its advertisement.

Here, the brand-W has the power rating of 7,640 W that is less than brand-Y. Advertiser cannot compare his brand using the name of Brand X, Y, or Z.

Therefore, the statement " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

To know more about Advertisement Rules:

brainly.com/question/13679377

7 0

3 years ago