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erastovalidia [21]
3 years ago
12

TRUE OR FALSE. if an object does not change its position at a given time interval, then it is at rest or its speed is zero or no

t accelerating
Physics
1 answer:
Andrew [12]3 years ago
3 0

Answer:

true

Explanation:

a body can only be accelerating and have speed if it's in motion

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You travel 23 meters north in 16 seconds, 5 meters south in 4 seconds, and 16 meters north in 18 seconds. Calculate your total d
dolphi86 [110]

Answer:

d: 44m

Δd:34  

Explanation:

d: 23+5+16= 44m

Δd: 23-5+16= 34m

4 0
2 years ago
As the amount of surface area increases, what happens to the rate of this reaction? If the antacid tablet were broken into eight
dangina [55]

as the surface  area increases the rate of reaction  also increases.

Explanation:

4 0
3 years ago
When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 40 cm .
vlada-n [284]

Answer:

m = 56.5 kg

Explanation:

Since the addition of mass on one piston caused a change in pressure head at the other. Diameter of the piston calculated is used as 0.46 m

Δm*g / Area = p * g * Δh   ..... Eq1

m = \frac{p*h*A}{g}

m = \frac{850 * 0.4 * pi*0.46^2}{4*9.81}\\\\m= 56.5 kg

8 0
3 years ago
Todo sistema heterogêneo é bifásico
strojnjashka [21]
I don't understand the language.....
3 0
3 years ago
A parallel-plate capacitor is connected to a battery and becomes fully charged. The capacitor is then disconnected, and the sepa
AnnZ [28]

Answer:

Increases

Explanation:

The expression for the capacitance is as follows as;

C=\frac{\epsilon _{0}A}{d}

Here, C is the capacitance, \epsilon _{0} is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.

It can be concluded from the above expression, the capacitance is inversely proportional to the distance. According to the given problem, the capacitor is disconnected from the battery and the distance between the plates is increased. Then, the capacitance of the given capacitor will decrease in this case.

The expression for the energy stored in the parallel plate capacitor is as follows;

E=\frac{Q^{2}}{2C}

Here, E is the energy stored in the capacitor, C is the capacitance and Q is the charge.

Energy stored in the given capacitor is inversely proportional to the capacitor. The charge on the capacitor is constant. In the given problem, as the distance between the parallel plates is being separated, the energy stored in this capacitor increases.

Therefore, the option (c) is correct.

8 0
3 years ago
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