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4 years ago

In most cases, what happens to a liquid when it cools?

Physics

1 answer:

erik [133]4 years ago

7 0

Answer:

Option (A) and (F)

Explanation:

As the liquid cools down, it means the temperature decreases the density of the liquid increases in most o the cases.

Now the volume is inversely proportional to the density of substance so density increases.

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We observe the wheels of buses and trucks are heavier than the wheels of cars and scooters why.

scoray [572]

Answer:

they carry a heavier load

Explanation:

4 0

2 years ago

You expend 1000 w of power moving a piano 10 meters in 5 seconds. how much force do you exert

Vinvika [58]

Answer:

Force, F = 500 N

Explanation:

Given that,

Power expanded, P = 1000 W

Distance moved by piano, d = 10 m

Time taken, t = 5 s

To find,

The force exerted by the person

Solution,

The rate at which the work is being done is called power delivered. Its formula is given by:

$P=\dfrac{W}{t}$

W is the work done, W = F × d

$P=\dfrac{Fd}{t}$

On rearranging the above formula to find F as :

$F=\dfrac{P t}{d}$

$F=\dfrac{1000\times 5}{10}$

F = 500 N

Therefore, the force exerted on the person is 500 N. Hence, this is the required solution.

7 0

3 years ago

Why will a sheet of paper fall slower than one that is crumbled into a ball

Zarrin [17]

It’s coming in contact with more air molecules than I would if it was in a ball because there is less surface area

4 0

3 years ago

Read 2 more answers

A simple ideal Brayton cycle uses argon as the working fluid. At the beginning of the compression, P1 = 15 psia and T1 = 70°F, t

Shtirlitz [24]

B I thing hope this helps

7 0

4 years ago

13.An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane tra

Murrr4er [49]

Answer:

The answer is 3.33m

Explanation:

The acceleration "a" is constant.

Acceleration is the variation of velocity over time,

$\frac{dv}{dt} = a$ .

solving the last equation

$\int_{v_0}^v dv = a\int_0^t dt \rightarrow v-v_0 = at$ ,

where $v_0=0$ because the airplane starts from rest.

Once again, velocity is the variation of distance over time.

$\frac{dx}{dt} = at \rightarrow \int_{x_0}^x dx = a\int_0^t t\ dt$

then

$x- x_0 = \frac{1}{2}at^2$

where $x_0=0$ if we consider the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).

If $x=1.11\ m$ at $t=1s$ , then

$a = \frac{2x}{t^2} = 2.22\ m/s^2$

and the final expression for the distance is

$x = 1.11 t^2$ .

If t = 2s, x = 4.44 m. Which means thad the additional distance is

$x(2s) - x(1s) = 4.44 - 1.11 = 3.33\ m$

8 0

4 years ago