I think it’s this but I’m not sure
Answer:
1577.20 ft³
Step-by-step explanation:
Cube of length = 12 ft = a
Hole diameter which is cutout = 4 ft = d
Hole radius which is cutout = 4/2 =2 ft = r
Volume of the cube = a³
⇒Volume of the cube = a×a×a
⇒Volume of the cube = 12×12×12
⇒Volume of the cube = 1728 ft³
The hole cut out will be in the shape of a cylinder
Volume of cylinder = πr²h
⇒Volume of cylinder = π×2²×12
⇒Volume of cylinder = 150.79 ft³
Now volume of the solid figure with hole cut out is
Volume of the cube - Volume of cylinder
=1728 - 150.79
=1577.20 ft³
∴ Volume of solid figure not including hole cutout is 1577.20 ft³
Answer:
$20
Step-by-step explanation:
Paul is making bread using a recipe. The amount of flour he uses is proportional to the number of loaves of bread. He uses 11 1/4 cups of flour to make 5 loaves of bread. If Paul used 18 cups of flour, and then sold the loaves of bread he made at a bake sale for $2.50 each, how much money would Paul make from his bread sales?
Step 1
Find out how many loaves of bread he can produce from 18 cups of flour
11 1/4 cups of flour = 5 loaves of bread
18 cups of flour = x loaves of bread
Cross Multiply
11 1/4 cups × x loaves = 18 cups × 5 loaves
x loaves = 18 cups × 5 loaves/ 11 1/4 cups
x loaves = 90 ÷ 11 1/4
x loaves = 90 ÷ 45/4
x loaves = 90 × 4/45
x loaves = 8 loaves of bread
He can produce 8 loaves of bread from 18 cups of flour.
Step 2
We are told that:
1 loaf of bread costs $2.50
Hence,
1 loaf of bread = $2.50
8 loaves of bread = $x
Cross Multiply
$x = 8 loaves of bread × $2.50
$x = $20
Therefore, Paul made $20 from his bread sales
Answer:
c and d are the correct answers
Answer:
70.7 meters.
Step-by-step explanation:
We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.
Since we know that diagonal of a square is product of side length of square and
. So we will find diagonal of our given square plaza by multiplying 50 by
.



Therefore, diagonal distance across the plaza is 70.7 meters.