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lubasha [3.4K]
4 years ago
6

Suppose a firm in a competitive market produces and sells 150 units of output and earns $1,800 in total revenue from the sales.

If the firm increases its output to 200 units, total revenue will be
Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
5 0

Answer: Total revenue would be $2400.

Step-by-step explanation:

Since we have given that

Number of units sold = 150

Total revenue = $ 1800

If the number of units = 200

Let the total revenue be 'x'.

Since there is direct variation.

According to question, we get that

\dfrac{150}{1800}=\dfrac{200}{x}\\\\150x=1800\times 200\\\\150x=360000\\\\x=\dfrac{360000}{150}\\\\x=2400

Hence, total revenue would be $2400.

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No wonder !

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3 years ago
Using a table of values, determine the solution to the equation below to the nearest fourth of a unit.
gayaneshka [121]
Let's call f(x) = 2x - 4 and g(x) = 3⁻ˣ + 1.

<span>First, you need to evaluate each function at the given values of x.</span>
f(1) = 2(1) - 4 = -2
f(3.25) = 2(3.25) - 4 = 2.50
f(2.5) = 2(2.5) - 4 = 1
f(2) = 2(2) - 4 = 0

Similarly:
g(1) = <span>3⁻¹ + 1 = 1.33
g(3.25) = </span><span>3⁻³'²⁵ + 1 = 1.03
g(2.5) = </span>3⁻²'⁵ + 1 = 1.06
g(2) = 3⁻² + 1 = 1.11

Now, look for the value of x for which f(x) ≈ g(x): this happens for x = 2.5
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4 0
3 years ago
Read 2 more answers
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Please solve the following system of equations <br> x+3y=8 <br> 2x-y=2
Anuta_ua [19.1K]

Answer:

(2,2)

Step-by-step explanation:

Given equations are

x+3y=8       eq(1)

2x-y=2        eq(2)

we'll solve the system of equation by substitution.

Adding -3y to both sides of eq(1),we get

x+3y-3y=8-3y

x+0=8-3y

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Put above value of x in eq(2),we get

2(8-3y)-y=2

16-6y-y=2

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Adding -16 to both sides of above equation,we get

-16+16-7y=-16+2

0-7y=-14

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Dividing by -7 to both sides of above equation,we get

-7y/-7=-14/-7

y=2

Putting y=2 in eq(3),we get

x=8-3(2)

x=8-6

x=2

hence, the solution for this system of equations is (2,2).

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