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2 years ago

Hows you day going:) When you woke up - Around lunch- Now-

Mathematics

1 answer:

Roman55 [17]2 years ago

4 0

Answer:

its going ok so far

Step-by-step explanation:

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What is 10.4% as a fraction?

AlladinOne [14]

10.4% as a fraction is 104/1000

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3 years ago

What is the slope of a ramp that rises 6 inches for every horizontal

san4es73 [151]

Rise/run, so 6/12=1/2

6 0

3 years ago

Please help me find the answer! Please explain how you got it!

Ksenya-84 [330]

Answer:

B. 4.5c + 4 = 24

Step-by-step explanation:

T = cx + py is the equation you are given.

T = 24 because it is the total amount of money you can spend.

x = 4.5 because each phone case costs 4.50 dollars

p = 2 because you bought 2 pop sockets.

y = 2 because each pop socket costs 2 dollars.

There is no c because you don't know the number of phone cases you bought.

Now, we have to substitute the values into the equation:

24 = 4.5x + 2(2)

24 = 4.5x + 4

4.5x + 4 = 24 <--- This is your answer

Hope this helps!

7 0

3 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

3 years ago

What property or properties are not used when solving the following equation -3(4x-8)=-36

BigorU [14]

Either B or D I’m not really sure but I know it’s one of this answers

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3 years ago

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