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3 years ago

Which excerpt from “Fish Cheeks” most appeals to a reader’s sense of sight?

Mathematics

1 answer:

saul85 [17]3 years ago

6 0

Answer:

The answer is C.My relatives licked the ends of their chopsticks and reached across the table,dipping into the dozen or so plates of food.

Step-by-step explanation:

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Write 3 ratios equivalent to 12/28

Firlakuza [10]

3/7 6/14 24/56 are all equivalent ratios for 12/28

8 0

3 years ago

In ΔVWX, \text{m}\angle V = (4x+3)^{\circ}m∠V=(4x+3) ∘ , \text{m}\angle W = (x+7)^{\circ}m∠W=(x+7) ∘ , and \text{m}\angle X = (5

NemiM [27]

Answer:

The value of x is 17

Step-by-step explanation:

The sum of the angles in a triangles is 180°

From the question:

In ΔVWX,

m∠V=(4x+3) ∘

m∠W=(x+7) ∘

m∠X=(5x+0) ∘ .

Hence:

m∠V + m∠W + m∠V = 180°

4x + 3 + x + 7 + 5x + 0 = 180°

Collect like terms

4x + x + 5x + 3 + 7 + 0 = 180°

10x + 10 = 180°

Subtract 10 from both sides

10x + 10 - 10 = 180° - 10

10x = 170

Divide both sides by 10

10x/10 = 170/10

x = 17

The value of x is 17

4 0

3 years ago

8.23 A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators

Kitty [74]

Answer:

The 95% confidence interval estimate for the population mean force is (1691, 1755).

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally.

The sample selected here is <em>n</em> = 30.

Thus, the sampling distribution of the sample mean will be normal.

Compute the sample mean and standard deviation as follows:

$\bar x=\frac{1}{n}\sum x=\frac{1}{30}\times 51702=1723.4\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{30-1}\times 232561.2}=89.55$

Construct a 95% confidence interval estimate for the population mean force as follows:

$CI=\bar x\pm z_{\alpha /2}\times\frac{s}{\sqrt{n}}$

$=1723.4\pm 1.96\times\frac{89.55}{\sqrt{30}}\\\\=1723.4\pm 32.045\\\\=(1691.355, 1755.445)\\\\\approx (1691, 1755)$

Thus, the 95% confidence interval estimate for the population mean force is (1691, 1755).

3 0

3 years ago

Helpppppp!

Dovator [93]

Answe The locations of E' and F' are E' (−8, 0) and F' (0, 4), and lines g and g' intersect at point F.

The locations of E' and F' are E' (−4, 0) and F' (0, 2), and lines g and g' are the same line.

The locations of E' and F' are E' (−2, 0) and F' (0, 1), and lines g and g' are parallel.

The locations of E' and F' are E' (−1, 0) and F' (0, 0), and lines g and g' are not related.

are your answer options I went with.. The locations of E' and F' are E' (−2, 0) and F' (0, 1), and lines g and g' are parallel.

Step-by-step explanation:

5 0

2 years ago

I need help I will give BRAINLEST

GREYUIT [131]

Answer:

25%

Step-by-step explanation:

To solve this, we can use the percent change formula shown in the picture attached below. $x_{2}$ is the new value, $x_{1}$ is the old value, and $C$ represents the change. For this problem, 80 is the new value and 64 is the old value. Let's plug those numbers into the formula and solve for the percent change:

$C = \frac{(80-64)}{64} \\$ × $100$

$C = \frac{16}{64}$ × $100$

$C = 0.25$ × $100$

$C = 25%$

Thus, the answer is 25%.

7 0

3 years ago