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Natalija [7]
4 years ago
14

The bottom of a cylindrical container has an area of 10 cm². The container is filled to a height whose mean is 5 cm, and whose s

tandard deviation is 0.3 cm. Let V denote the volume of fluid in the container.
Find μv and σv.
Mathematics
1 answer:
disa [49]4 years ago
5 0

Answer:

μv =50 cm^{3}

σv= 3 cm^{3}

Step-by-step explanation:

Volume is found by multiplying the area and height. Since we're given both area and height of 10 and 5 cm respectively then

μv =A.h= 10*5= 50 cm^{3}

The standard deviation of the volume will be

σv= 0.3*10= 3 cm^{3}

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if pentagon abcd was reflected over the axis y-axis, reflected over the x-axis, and rotated 180, where would be point A' lie
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4 0
3 years ago
Add. 4 7/12+2 3/4+7 5/12
mihalych1998 [28]

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C.14¾

3 9⁄10

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\frac{4}{5}  + 3 \frac{1}{10}  =  \frac{8}{10}  + 3 \frac{1}{10}  = 3 \frac{9}{10}

4 \frac{7}{12}  + 2 +  \frac{3}{4}  + 7 \frac{5}{12} =  13 \frac{12}{12}  +  \frac{3}{4}  = 14 +  \frac{3}{4}  = 14 \frac{3}{4}

I am joyous to assist you anytime.

3 0
3 years ago
Pls help me in these two little exercises about the slope.
den301095 [7]

Answer:

3)  y=\dfrac35x+\dfrac25

4) a)  y=-2x+7

  b)  y=\dfrac12x+\dfrac92

Step-by-step explanation:

<u>Exercise 3</u>

-3x + 5y = 2

\implies 5y = 3x + 2

\implies y=\dfrac35x+\dfrac25

<u>Exercise 4</u>

a) If L2 is parallel to L1, it has the same slope (gradient) ⇒ m = -2

If L2 passes through point (3, 1):

y-y_1=m(x-x_1)

\implies y-1=-2(x-3)

\implies y=-2x+7

So L2 = L1

b) If L3 is perpendicular to L1, then the slope of L3 is the negative reciprocals of the slope of L1  ⇒  m = \dfrac12

If L3 passes through point (-5, 2):

y-y_1=m(x-x_1)

\implies y-2=\dfrac12(x+5)

\implies y=\dfrac12x+\dfrac92

4 0
2 years ago
Read 2 more answers
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