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3 years ago

A three dimensional circular shape

Chemistry

2 answers:

scoundrel [369]3 years ago

5 0

Your answer is a sphere

Bond [772]3 years ago

4 0

A three dimensional circular shape would be a sphere :)

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[Gradpoint-Question AK-4] Which equation represents a combustion reaction?

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Would the answer be d wouldn't it

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Propenoic acid, C3H4O2, is a reactive organic liquid that is used in the manufacturing of plastics, coatings, and adhesives. An

Shkiper50 [21]

Answer:

C = 39%

H = 5.43%

Explanation:

Firstly, we calculate the number of moles of each.

For carbon, we use carbon iv oxide

Mass here = 0.636g

Number of moles of carbon iv oxide = mass of carbon iv oxide ÷ molar mass of carbon iv oxide. Molar mass = 44g/mol

Number of moles = 0.636 ÷ 44 = 0.014mole

Since 1 mole of carbon iv oxide contains 1 mole carbon, 0.014 mole of carbon iv oxide is also produced.

Mass of carbon = 0.014 × 12 = 0.173g, where 12 is the a.m.u of carbon.

For hydrogen, we use water .

Mass of water = 0.220g

No of moles of water = 0.22 ÷ 18 = 0.012 mole

1 mole of water has two moles of hydrogen, thus the amount of hydrogen produced = 0.012 × 2 = 0.024mole

Mass of hydrogen produced = 0.024 × 1 = 0.024g

The percentage composition are as follows:

Carbon = 0.173/0.442 × 100 = 39%

Hydrogen = 0.024/0.442 × 100 = 5.43%

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3 years ago

write down the name and molecular formula of the compound which gives hydrogen ion and chloride ion in the solution state.

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Answer:

Hydochloric acid

HCl

Explanation:

The name of the compound that gives hydrogen ion and chloride ions in the solution state is Hydrochloric acid.

Hydrochloric acid is made up of one atom of hydrogen and 1 atom of chlorine. We can also say, it is made up of 1 mole of hydrogen and 1 mole of chlorine.

The formula of this compound is HCl;

In solution:

HCl $_{aq}$ → H⁺ + Cl⁻

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2 years ago

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step by step explanation:

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The molar concentration of the KI_3 solution is 0.251 mol/L.

Step 1. Write the balanced chemical equation

I_3^(-) + 2S_2O_3^(2-) → 3I^(-) + S_4O_6^(2-)

Step 2. Calculate the moles of S_2O_3^(2-)

Moles of S_2O_3^(2-)

= 27.9 mL S_2O_3^(2-) ×[0.270 mmol S_2O_3^(2-)/(1 mL S_2O_3^(2-)]

= 7.533 mmol S_2O_3^(2-)

Step 3. Calculate the moles of I_3^(-)

Moles of I_3^(-) = 7.533 mmol S_2O_3^(2-)))) × [1 mmol I_3^(-)/(2 mmol S_2O_3^(2-)] = 3.766 mmol I_3^(-)

Step 4. Calculate the molar concentration of the I_3^(-)

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