To satisfy the law of conservation of mass
Answer:
Explanation:
Aly's teacher said some bacteria can be as small as 0.00365 cm long.
In this problem, we need to write the length of the bacteria written in scientific notation. Any number can be written in the form of scientific notation as follows :
a is a real no and b is an integer
In the given number, there are two zeroes before 3. We need to shift the decimal after 3. It can be done as follows :
Hence, this is the required solution.
<span>The balanced chemical equation for this reaction is:
2NaOH (aq)+H2SO4 (aq) → Na2SO4 (aq)+2H2O (l)
According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.
The no. of moles of H2SO4 is calculated using the equation:
mol solute = (molarity) (L soln)
mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4
As per the equation, the number of moles of NaOH used is:
0.02 moles of H2SO4 (2 mol NaOH) (1 mol H2SO4) = 0.04 moles of NaOH
Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula :
Molarity = mol solute/L soln = 0.04 mol NaOH/0.06 L = 0.67 M
Therefore, the concentration of NaOH is 0.67 M.</span>
Answer:
Fluorine is a <em>non-metal, fills its shell by gaining one electron </em>and<em> becomes a negatively charged ion.</em>
Explanation:
Fluorine have seven electrons in its outermost shell. This means that fluorine is located in Group 17(<em>Halogens</em>) in the Periodic Table. Note that halogens are non-metal elements. So fluorine is a non-metal.
Fluorine fills its shell by gaining one electron because it only needs one electron to achieve stable octet electron arrangement. ( it's easier to gain one electron than to lose all seven electrons in the outermost shell)
As fluorine atom gain one electron to achieve stable octet electron arrangement, its number of electrons becomes greater than its number of protons. So it becomes a negatively charged ion.
Answer:
ACETYL-CoA, FADH
2 NADH
acetyl-CoA
Explanation: Beta oxidation of carbons of fatty acid acid molecules leads to the formation Acetyl-CoA, FADH and NADH.
The overall reaction for the process
Cn-acyl-CoA + FAD + NAD+
+ H
2O + CoA → Cn-2-acyl-CoA + FADH
2 + NADH + H+
+ acetyl-CoA.
formula of NADH is C21H27N7O14P2
formula of FADH is C27H35N9O15P2.
Both NADH(Nicotinamide adenine dinucleotide) and FADH( Flavin adenine dinucleotide) are
formular for Acetyl CoA IS C23H38N7O17P3S.
Beta oxidation is a breakdown process taking place in living systems which catabolises the fatty acids through glycolysis or fermentation leading to the release of Acetyl CoA, NADH AND FADH2.
