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Bingel [31]
3 years ago
7

4.93x10^25/(6.02 x 10^23)

Chemistry
1 answer:
yuradex [85]3 years ago
8 0

Answer:

2.96786x10^49

Explanation:

multiply using law of indices

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Colligative properties are dependent only on the number of particles in a solution, and not their identity. (select all that app
Cerrena [4.2K]
The answer will be apart of a 60 caculace so it will equal to a efficacy amount so d
7 0
2 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
miskamm [114]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

6 0
3 years ago
Pb(NO3)2+K2CrO4 --&gt; PbCrO4+KNO3 <br> How do you balance this?
belka [17]

Answer:

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃

Step-by-step explanation:

The unbalanced equation is

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + KNO₃

Notice that the complex groups like NO₃ and CrO₄ stay the same on each side of the equation.

One way to simplify the balancing is to replace them with a single letter.

(a) For example, let <em>X = NO₃</em> and <em>Y =CrO₄</em>. Then, the equation becomes

PbX₂ + K₂Y ⟶ PbY + KX

(b) You need 2X on the right, so put a 2 in front of KX.

PbX₂ + K₂Y ⟶ PbY + 2KX

(c) Everything is balanced. Now, replace X and Y with their original meanings.  The balanced equation is

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃

5 0
3 years ago
What atom has the larger atomic radius Ca or Ni ?
Harrizon [31]

your answer is CA

says quizlet have and its right thanks

5 0
3 years ago
C3H8 + 5O2 → 3CO2 + 4H2O
trasher [3.6K]

Answer:

16.5moles of CO2

Explanation:

Molar mass of O2 is 32g/Mol

No of mole = 880/32 = 27.5 moles

27.5 Mol of O2 gives X mole of CO2

5 mole of O2 gives 3 moles of CO2

No of mole of CO2 = (27.5×3)/ 5 = 16.5moles

7 0
3 years ago
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