Answer:
C as C^unt
Step-by-step explanation:
Set up a proportional relationship:
xf/1n=(f/5)/(n/3)
xf/1n=3f/(5n) multiply both sides by 1n
xf=3f/5 so
x=3/5
Dave must mix in 3/5 of a cup of fruit with a single cup of nuts.
You could of also just noted that you need to multiply 1/5 times 3 because 1/5 mixes with just 1/3 of a cup of nuts...
I/3 of 123 is 41
41 dollars are taken off, so 123-41=82
the sale price is 82 dollars
Factoring the equation:
3x^2 + 1/2 x 7(3)
3x^2 + 1/2 x 21
3 (x^2 + 1/2 x 21)
3 (x^2 + 7/2)
3 x 1/2 (2x^2 +7)
3/2 (2x^2 + 7)
Consider x=0.
The output of the function y=x is y=0.
The output of the function y=x+5 is y=0+5, or y=5.
The value 5 is not 5 less than 0, not 1/5 of 0, and not 5 times 0. Rather, it is 5 more than 0, corresponding to selection ...
... C. Each output of y=x+5 is 5 more than the corresponding output of y=x.