Answer:We're looking for a,b such that
\dfrac{9x-20}{(x+6)^2}=\dfrac a{x+6}+\dfrac b{(x+6)^2}
Step-by-step explanation:
Answer:
No this is not a function.
Step-by-step explanation:
This is not a function because some of the x-values repeat, which is not how a function works. For this to be a function, each x-value would have to be different. In this case, the 4 and 5 repeat in the x-values.
If this answer is correct, please make me Brainliest!
Given
f(x)= -3x - 5
g(x)= 4x - 2
Find
(f - g)(x)
substitute the f and g values in (f - g)
(f - g)(x)= -3x - 5 - (4x - 2)
change the signs in parentheses because there is a negative sign in front of the parentheses
(f - g)(x)= -3x - 5 - 4x + 2
combine like terms
(f - g)(x)= -7x - 3
ANSWER: (f - g)(x)= -7x - 3
Hope this helps! :)
-A terminating decimal is a decimal that NEVER ends
1/15 = 0.666666666.....
Therefore, 1/15 is a terminating decimal.
