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Nimfa-mama [501]
3 years ago
6

Do you think tress could reduce the negative effects of climate change? why or why not

Biology
2 answers:
Oxana [17]3 years ago
5 0

Answer:

Hi there, Here is what I think

Trees can't reduce the negative effects of climate change because climate change throws off their functions (ex. Trees' leaves fall during the fall season but if its a lot warmer close to summer weather during fall season) it can mess up the way they function at a certain point in the seasons with that trees won't be able to function properly if the weather changes all of a sudden from scorching hot summer to a blizzard all of a sudden which can kill trees. Trees can hibernate in the Winter and bloom around Spring/Summer time but if you have wintery weather during summer it will kill them. So no trees can't reduce the negative effects of climate changes hence why people are scared over climate change because if the trees die we can die too without the oxygen trees and other plants provide for us.

Hope this helped :)

Anuta_ua [19.1K]3 years ago
5 0
In my opinion no because trees change with their climate
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7 0
3 years ago
A population of Muscovy ducks contains 13 birds with black masks and 37 birds with red masks. Red masks are the dominant trait.
Semmy [17]

Answer: Black allele has frequency of 0.14.

              Red allele has frequency of 0.86.

             The frequency of heterozygotes is 0.241

Explanation: <em>Hardy-Weinberg model </em>states the frequency of alleles in a population will stay in equilibrium as long as there are external influences. It is also used to determine alleles frequencies using the following equations:

p+q=1

p^{2}+2pq+q^{2}=1

p represents frequency of dominant allele;

q represents frequency of recessive allele;

2pq is frequency of heterozygotes;

For the frequency of red allele, which is dominant, we can use:

p^{2}=\frac{37}{13+37}

p^{2}=\frac{37}{50}

p^{2}=0.74

p=\sqrt{0.74}

p = 0.86

For the black allele:

p+q=1

q=1-p

q=1-0.86

q = 0.14

Frequency of heterozygotes is

2pq = 2(0.86)(0.14)

2pq = 0.241

<u>Frequencies for a population of Muscovy ducks are </u><u>0.86 for red allele, 0.14 for black allele and 0.241 for heterozygote.</u>

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