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Elza [17]
3 years ago
5

The Olympic-size pool at the recreational center is a right rectangular prism 50m long and 25m wide. The pool contains 3000m3 of

water. How deep is the water in the pool?
Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0

Step-by-step explanation:

50 * 25 = 1250 square meters

3000 / 1250 = 2.4 meters deep

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What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
A football player is running the length of a 100 yard long football field. For the first part of the field, he runs at a rate of
notka56 [123]

Answer:

\frac{2}{5}th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = \frac{x}{2} seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = \frac{Distance}{Speed}

= \frac{100-x}{4} seconds

Now total time taken by the player can be represented by the equation

\frac{x}{2}+\frac{100-x}{4}=40

Now we can solve this equation for the value of x.

\frac{2x+100-x}{4}=40

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

= \frac{40}{100}

= \frac{2}{5} or 40%

Therefore, \frac{2}{5}th part of the field was covered in second sprint.

5 0
3 years ago
Alex is standing 60 feet from the base of a flagpole. He measures the angle of elevation to the top of the pole as 35º. Vera is
ivanzaharov [21]

Answer:

49.4 degrees

Step-by-step explanation:

In Triangle AXY,

Tan 35^0=\frac{|XY|}{60} \\|XY|=60*Tan 35^0=42.01\:feet\\$Therefore, Height of the pole=42.01 \:feet

We want to determine the angle of elevation from the point Vera is standing to the top of the flagpole, which is the angle at V in the diagram.

In Triangle XVY

|VY|=36 feet

Tan \theta=\frac{|XY|}{|VY|} \\Tan \theta=\frac{42.01}{36}\\ \theta=arctan(\frac{42.01}{36})\\ \theta=49.4^0

Therefore, the angle of elevation from the point Vera is standing to the top of the flagpole is 49.4 degree to the nearest tenth of a degree.

4 0
4 years ago
The pH of solution A is 2.4​, while the pH of solution B is 9.4.
pishuonlain [190]

Answer:

The answer to your question is below

Step-by-step explanation:

pH definition

                         pH = - log [H⁺]

a) For pH = 2.4, solution A

                       2.4 = -log[H⁺]

                      [H⁺] = antilog⁻².⁴

                      [H⁺] = 0.00398

  For pH = 9.4, solution B

                       [H⁺] = antilog⁻⁹.⁴

                       [H⁺] = 3.98 x 10⁻¹⁰

b) Divide hydrogen-ion concentration of solution A by hydrogen-ion concentration of solution B.

                             0.00398 / 3.98 x 10⁻¹⁰

                             10000000 times

c) By 7, because 7 is the number of zeros

3 0
3 years ago
Simplify the expression <br> 15+(x+9)+3
Allushta [10]
27 + x is the simplified expression.
4 0
4 years ago
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