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finlep [7]
3 years ago
15

Find the area of the shape shown below.

Mathematics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

24

Step-by-step explanation:

the area of the triangle is 4 x 2, which equals 8.

Then you calculate the area of the rectangle.

Area of Rectangle = L x W or (in this case) 8 x 4

8 x 4 = 32

Then you subtract the area of the triangle from the area of the rectangle

So, your equation would be 32 - 8  = 24

Therefore, the area of the shape is 24

jenyasd209 [6]3 years ago
3 0

Answer:  

24

Step-by-step explanation:

the area of the triangle is 4 x 2, which equals 8.

Then you calculate the area of the rectangle.

Area of Rectangle = L x W or (in this case) 8 x 4

8 x 4 = 32

Then you subtract the area of the triangle from the area of the rectangle

So, your equation would be 32 - 8  = 24

Therefore, the area of the shape is 24

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Is 8.001 bigger than 8.002​
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False

Step-by-step explanation:

8.001 is not greater than 8.002

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the volume of a cube depends on the length of its sides.this can be written in function notation as v(s). what is the best inter
Sergeeva-Olga [200]

<u>Answer:</u>

Interpretation: A cube with sides of 4 units each has a volume of 64 units³.

<u>Explanation:</u>

As v(s) represents the volume of the cube, s represents the length of the sides.

∴ v(4) represents the volume of a cube with sides of  units, and the volume is 64 units³

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Anyone want to answer the number for X???????
Anna007 [38]

Answer:

\frac{\sqrt{10} }{2}

Step-by-step explanation:

Using cosine (since that is adjacent over hypotenuse), cos(60)=1/2 so your answer is hypotenuse*1/2=\sqrt{10}*\frac{1}{2}=\frac{\sqrt{10} }{2}

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melisa1 [442]

It’s 2 and 8 as the left end of the box is Q1 and the right end of the box is Q3. I’m a little rusty on box and whisper plots but this should be correct.

7 0
2 years ago
The height after t seconds of an object projected upward with an initial velocity of 48 feet per second from a 210-foot tower ca
svetlana [45]

Given:

The height h of an object after t seconds is

h=-16t^2+48t+210

The height of a neighboring 50-foot tall building is modeled by the equation h=50.

The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.

To find:

The statement which describes the validity of these solutions.

Solution:

We have,

h=-16t^2+48t+210

Here, t is the time in seconds.

For t=-2,

h=-16(2)^2+48(-2)+210

h=-64-96+210

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For t=5,

h=-16(5)^2+48(5)+210

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So, the value of h is 50 at t=-2 and t=5.

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