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Roman55 [17]
3 years ago
7

What is 389*1094 need help

Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

i agree with the comments its  425566

Step-by-step explanation:

MAY GOD BLESS YOU

have a good day :D  

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laila [671]
Hello!

As we can see, our first amount was 95 for the one machine. We are not multiplying it by anything from the second day as it was used the first. There is no 95 in B, and in C and D it is multiplied.

In A, we have a base of 95, plus 25 multiplied by x and y, and this fits the scenario perfectly. Our answer is A.

I hope this helps!


3 0
3 years ago
A shirt is on sale for $30. It was originally $40 What is the percent of the decrease?​
SpyIntel [72]

Answer:

25% percent

Step-by-step explanation:

4 0
3 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
To find the number of bacteria, B, after t hours, use the formula B =1001.32t. How many bacteria were there
masha68 [24]

Answer:

The answer to your question is : B = 5007

Step-by-step explanation:

Formula

               B = 1001.32t

t = 5 hours,

Then

             B = 1001.32 (5)

            B = 5006.6 ≈ 5007

4 0
3 years ago
Find the perimeter I will give brainliest if you are correct
solong [7]

Answer:55 :o

Step-by-step explanation:

4 0
3 years ago
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