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Aleksandr [31]
3 years ago
5

A breakfast diner ordered milk with 1.5% fat but 30 liters of milk with 5% fat were delivered. How many liters of milk with 0% f

at should the waitress add to the delivery to get milk with 1.5% fat?
Mathematics
1 answer:
avanturin [10]3 years ago
6 0

Answer:

70 Litres

Step-by-step explanation:

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Look at pic and answer plzzzzz its a DLA (7th)
Zigmanuir [339]

Answer: 187.96 cm

Step-by-step explanation: First you need to convert all of the units into centimeters. To do this you need to convert the 6 feet into inches. Since there are 12 inches in a foot, 6 feet is equal to 72 inches. Next add the 2 inches to 72, and now this means Tyson is 74 inches tall. Lastly convert the inches into centimeters by multiplying 74 by 2.54, which equals 187.96.

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The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

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