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Sindrei [870]
4 years ago
7

9 to 2

Mathematics
1 answer:
Arlecino [84]4 years ago
5 0

<u>Answer:</u>

\frac { 4 } { 5 }

<u>Step-by-step explanation:</u>

We are given the following two points and we are to find the slope of the line which passes through these points:

(3.-1) and (-2,-5)

The formula of the slope is given by:

Slope = \frac { y _ 2 - y _ 1 } { x _ 2 - x _ 1 }

Substituting the given coordinates in the above formula:

Slope = \frac { - 5 - ( - 1 ) } { - 2 - 3 } = \frac { 4 } { 5 }

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Answer:

6.8%

Step-by-step explanation:

\frac{21447.20}{315400}  When you divide this, you get 0.068.  This is in decimal form.  To change to a percent move the decimal to places to the right 6.8%

8 0
2 years ago
Find the coordinates of point S On QR such that the ratio of QS to SR is 1:3 Q(2,5) R(-2,-3) <br>​
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4 years ago
James has a board that is 3/4 foot long. He wants to cut the board into pieces that are each 1/8 foot long. How many pieces can
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Step-by-step explanation:

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4 years ago
Need help ASAP please<br> How many solutions are there to the following equation:<br> a+5 = -5+5
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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the amount to which $2,500 will grow if interest of 6.75% is compounded quarterly for 10
andreev551 [17]

Answer:

Part a

For this case n = 4. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{4})^{4*10}= 4882.506

Part b

For this case n = 365. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{365})^{365*10}= 4909.776

Step-by-step explanation:

We can use the future vaue formula for compound interest given by:

A= P(1+ \frac{r}{n})^{nt}

Where P represent the present value, r=0.0675 , n is the number of times that the interest is compounded in a year and t the number of years.

Part a

For this case n = 4. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{4})^{4*10}= 4882.506

Part b

For this case n = 365. If we use the future value formula we got:

A= 2500 (1+ \frac{0.0675}{365})^{365*10}= 4909.776

5 0
3 years ago
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