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Hitman42 [59]
4 years ago
14

What effect does nuclear radiation have on atoms?

Chemistry
1 answer:
fiasKO [112]4 years ago
8 0

Answer:

Unstabilizing the nucleon or their electron cloud.

Explanation:

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Select the set of coefficients that would balance the following equation:
vitfil [10]
I think it’s the second one
5 0
3 years ago
A substance is tested and has a pH of 7.0. How would you classify it?
Alexandra [31]

Answer:

C

Explanation:

The substance would be classified as neutral, so C.

5 0
3 years ago
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Which of the following is NOT evidence for a chemical reaction?
miss Akunina [59]

Answer:

c

Explanation:

color chance - evidence

gas formation - is evidence

melting - is not (because its only a change in state, eg. ice--> melts into water) melting is an example of physical chance

odor - is evidence

4 0
2 years ago
Which is an example of chemical weathering?
kobusy [5.1K]

Answer:

b. the layer of oxide formed on statues made of metal

Explanation:

Chemical weathering is a process whereby rocks are disintegrated or weathered causing a chemical reaction thereby leading to change in the parent rock constituents .

In chemical weathering a new substance is usually formed after the weathering takes place.

From the question the layer of statue made by metal will likely form oxides of those metals. Example Silver will react with oxygen to form an entirely new substance like silver(i)oxide.

7 0
3 years ago
The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

8 0
3 years ago
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