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OlgaM077 [116]
3 years ago
9

A substance is tested and has a pH of 7.0. How would you classify it?

Chemistry
2 answers:
Alexandra [31]3 years ago
5 0

Answer:

C

Explanation:

The substance would be classified as neutral, so C.

Tresset [83]3 years ago
3 0
<h2>Answer:  C. Neutral</h2>

Explanation:

A substance with a pH of 7.0 is NEUTRAL (option c).

Pure water has a pH of 7.0.

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Ludmilka [50]

Answer:

NEEE

Explanation:

5 0
3 years ago
Calculate the total pressure in a 10.0 liter flask at 27°C of a sample of gas that contains 6.0 grams of hydrogen, 15.2 grams of
motikmotik

Answer:

The total pressure is 27.8 atm

Explanation:

From the ideal gas equation,

PV = nRT

P (total pressure) = nRT/V

n (total moles of gases) = (6/1 moles of hydrogen) + (15.2/14 moles of nitrogen) + (16.8/4 moles of helium) = 6+1.1+4.2 = 11.3 moles

R = 0.082057L.atm/gmol.K, T = 27°C = 27+273K = 300K, V = 10L

P = 11.3×0.082057×300/10 = 27.8 atm

7 0
3 years ago
the reversible reaction N2(g) 3H2(g) &lt;--&gt; 2NH3(g) produces ammonia, which is a fertilizer. At equilibrium, a 1L flask cont
Alik [6]

Answer:

Explanation:

the chemical equilibrium constant can be easily calculated since the concentrations at equilibrium are given.the calculation shows the value of Kc for the reversible reaction and forward reaction

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7 0
3 years ago
What happens to glucose in the Calvin cycle? <br><br> Plz help
Leona [35]

The reactions of the Calvin cycle add carbon from carbon dioxide in the atmosphere to a five-carbon molecule known as RuBP. These reactions use chemical energy that were produced in the light reactions, from NADPH and ATP. The final product of the Calvin cycle is glucose.

7 0
4 years ago
Prob.: Consider the combustion of butane (C4H10):
never [62]

<u>Answer:</u> The moles of carbon dioxide formed in the reaction is 20 moles.

<u>Explanation:</u>

We are given:

Number of moles of butane = 5.0 moles

The chemical reaction for the combustion of butane follows the equation:

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(l)

As, oxygen is present in excess. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of products.

By stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide.

So, 5 moles of butane will produce = \frac{8}{2}\times 5=20mol of carbon dioxide.

Hence, the moles of carbon dioxide formed in the reaction is 20 moles.

7 0
3 years ago
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