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inna [77]
3 years ago
9

Plz do this i need help ill give u brailiest

Chemistry
2 answers:
Musya8 [376]3 years ago
8 0

1. C

2. B

3. B

4. sorry, but we cant see the pictures. thats all I can do.

-Chad

VashaNatasha [74]3 years ago
6 0

Answer:

(1) Turgor, an internalstimulus, refers to <u>energy</u><u> </u>in a plant cell.

(2) Osmosis moves materials in and out of the plant cell from areas of <u>low </u><u>to </u><u>high</u><u> </u>concentration?

(3) When a plant is hypertonic,what is happening in the plantcell, and what will the plantlook like?

→ <u>A. The vacuole is not full and the plant is wilted.</u>

(4) What picture at the bottom of the page represents equilibrium orbalance in a cell?

→ Sorry the picture is not given

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Sulfur trioxide. hope this helps
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Which could be the catalyst in a chemical reaction?
AlekseyPX

Answer:  C. enzyme

Explanation:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

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3 years ago
A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
andrew-mc [135]

Answer: The molecular formula for the given organic compound X is C_6H_{8}O_7

Explanation:

We are given:

Mass of CO_2=4.13g

Mass of H_2O=1.13g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, =\frac{12}{44}\times 4.13=1.13g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, \frac{2}{18}\times 1.13=0.125g of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles

Moles of Hydrogen =\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles

Moles of Oxygen =\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = \frac{0.094}{0.094}=1

For Hydrogen = \frac{0.125}{0.094}=1.33

For Oxygen = \frac{0.109}{0.094}=1.16

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is C_6H_8O_7

Empirical mass = 6\times 12+8\times 1+7\times 16=192g

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

Putting values in above equation, we get:

n=\frac{192g/mol}{192g/mol}=1

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_6H_8O_7\times 1=C_6H_{8}O_7

Thus molecular formula for the given organic compound X is C_6H_{8}O_7

7 0
3 years ago
What is matter in science
german

Matter in science is how much space you have.

Hope this helps

God bless you

- Kayla <3

3 0
3 years ago
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