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inna [77]
3 years ago
9

Plz do this i need help ill give u brailiest

Chemistry
2 answers:
Musya8 [376]3 years ago
8 0

1. C

2. B

3. B

4. sorry, but we cant see the pictures. thats all I can do.

-Chad

VashaNatasha [74]3 years ago
6 0

Answer:

(1) Turgor, an internalstimulus, refers to <u>energy</u><u> </u>in a plant cell.

(2) Osmosis moves materials in and out of the plant cell from areas of <u>low </u><u>to </u><u>high</u><u> </u>concentration?

(3) When a plant is hypertonic,what is happening in the plantcell, and what will the plantlook like?

→ <u>A. The vacuole is not full and the plant is wilted.</u>

(4) What picture at the bottom of the page represents equilibrium orbalance in a cell?

→ Sorry the picture is not given

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What is the name of a solution whose concentration of solute is equal to the maximum concentration that is predicted from the
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C because it is maximumly contracted
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An electron in the n=7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 2166 nm
Feliz [49]

n'  =   4 ( solution is attached below )


6 0
3 years ago
What is the chemical formula for iron(II) hydroxide?
makkiz [27]
Answer: Fe(OH)2

Explanation: Fe has a charge of 2+ and OH has a charge of 1-. Switch the charges of the two elements to get the formula of Fe(OH)2.
4 0
2 years ago
How much of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
Ivan

Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.05M\\V_2=25.0mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.05\times 25.0\\\\V_1=2.5mL

Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

6 0
3 years ago
Water has a specific heat of 4.18 J/g°C. If 35.0 g of water at 98.8°C loses 4.94 kJ of
stira [4]

Answer:

65°C

Explanation:

Formula for calorimetry is:

Q = C . m . ΔT

Where Q is heat, C is specific heat, m is mass and ΔT is the difference between final T° and initial.

We have all data to replace.

First of all, we convert kJ to J → 4.94 kJ . 1000 J / 1 kJ = 4940 Joules

We made this conversion because the unit of C, is in J

As heat is lost, we have to think in a negative value. Let's replace:

- 4940 J = 4.18 J/ g °C . 35 g . ( Final T° - 98.8°C)

- 4940 J / (4.18 J/ g °C . 35 g) =  Final T° - 98.8°C

Final T° = - 4940 J / (4.18 J/ g °C . 35 g) + 98.8°C

Final T° = 65.03 °C

Notice, that this answer has sense because as T° decreased, heat has been lost.

3 0
3 years ago
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