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Vladimir79 [104]
3 years ago
9

Which natural resource needed to be mined to produce a digital phone?

Chemistry
1 answer:
erik [133]3 years ago
7 0

Answer:

Copper

Explanation:

copper is used in the wiring of the phone

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Good idea!maybe I should try that
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3 years ago
I needa know the first one help✋
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Answer: Soil permeability is the property of the soil to transmit water and air and is one of the most important qualities to consider for fish culture. A pond built in impermeable soil will lose little water through seepage. The more permeable the soil, the greater the seepage.

Explanation:

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3 years ago
The weak base ionization<br> constant (Kb) for HCO3 is<br> equal to:
hammer [34]

Weak bases are alkaline solution that does not get completely dissociated. The dissociation constant will be the ratio of the concentration of the products to the reactants.

<h3>What is a weak base ionization constant?</h3>

The weak base ionization constant is the equilibrium constant that is given as the division of the products of the ionization to the concentration of the reactants.

The reaction for HCO₃ is given as:

HCO₃⁻ + OH⁻ ⇄ CO₃²⁻ + H₂O

The value of Ka for the given reaction will be:

Ka = [CO₃²⁻][H₂O] ÷ [HCO₃⁻ ][OH⁻]

Therefore, the Ka of the weak carbonic acid is given as the ratio of the concentration of the products to the reactants.

Learn more about the weak ionization constant here:

brainly.com/question/27200344

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8 0
1 year ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
shutvik [7]

Answer:

  • <u>79%</u>

Explanation:

<u>1) Balanced chemical equation:</u>

  • 2S + 3O₂ → 2SO₃

<u>2) Mole ratio:</u>

  • 2 mol S : 3 mol O₂ : 2 mol SO₃

<u>3) Limiting reactant:</u>

  • Number of moles of O₂

        n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂

  • Number of moles of S:

         n = 7.0 g / 32.065 g/mol = 0.2183 mol S

  • Ratios:

        Actual ratio: 0.1875 mol O₂ / 0.2183 mol S =0.859

        Theoretical ratio: 3 mol O₂ / 2 mol S = 1.5

Since there is a smaller proportion of O₂ (0.859) than the theoretical ratio (1.5), O₂ will be used before all S be consumed, and O₂ is the limiting reactant.

<u>4) Calcuate theoretical yield (using the limiting reactant):</u>

  • 0.1875 mol O₂ / x = 3 mol O₂ / 2 mol SO₃

  • x = 0.1875 × 2 / 3 mol SO₃ =  0.125 mol SO₃

<u>5) Yield in grams:</u>

  • mass = number of moles × molar mass = 0.125 mol × 80.06 g/mol =  10.0 g

<u>6) </u><em><u>Percent yield:</u></em>

  • Percent yield, % = (actual yield / theoretical yield) × 100
  • % = (7.9 g / 10.0 g) × 100 = 79%
6 0
3 years ago
Write the name for each of the following chemical formulas. <br> d. P3N5 (for doping semiconductors)
rewona [7]

Answer:

Triphorphorus Pentanitride

Explanation:

since there are three phosphorus use the prefix tri-, since there are five nitrogen use the prefix penta. tri=3, penta=5. then add a suffix -ide to the end of nitrogen. that will give you triphosphorus pentanitride.

3 0
2 years ago
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