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Nataly_w [17]
3 years ago
10

Please help me it's urgent​

Chemistry
2 answers:
Kruka [31]3 years ago
7 0
C3H8 + 5 O2 = 3CO2 + 4H20

tia_tia [17]3 years ago
3 0

Answer:

a) NaSO4+Bacl2 -> Baso4+2Nacl

b) 4C3H3+15O2 -> 12CO2+6H2O

Explanation:

The atoms at the reactants is equal with the product.

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Which of the following is the correct sequence of the planets in order: CLOSEST to the sun --> FURTHEST away from the sun
Strike441 [17]
The answer is A M.V.E.M.J.S.U.N
3 0
3 years ago
Read 2 more answers
Why is cyanide ion negatively charged?
Bogdan [553]
The cyanide is CN^{-}
A carbon atom has 4 valance electrons and nitrogen has 5. Below is a Lewis-dot-structure of cyanide.
:N≡C.
The carbon atom is still one electron short of having a full octet and so it will seize another electron from almost anything, making the cyanide ion negative and whatever it took the electron from it now positive.
8 0
3 years ago
2KI - 2K + 12
Troyanec [42]

Answer:

The answer to your question is 3.5 moles of I₂    

Explanation:

Data

moles of I₂ = ?

moles of KI = 7

Balanced chemical reaction

                2KI  ⇒   2K  +  I₂

Process

To solve this problem use proportions and cross multiplication. Use the coefficients of the balanced chemical reaction for this proportion.

                2 moles of KI --------------------- 1 mol of I₂

                7 moles of KI  --------------------  x

                    x = (7 x 1) / 2

-Simplifying

                    x = 7/2

-Result

                   x = 3.5 moles of I₂        

4 0
3 years ago
Why is the C-14/C-12 ratio used to date once-living organisms?
vredina [299]
D. An organism stops taking in carbon when it dies.
6 0
3 years ago
Choose the balanced equation for the reaction. Au3+(aq) + Cu+(aq) → Au(s) + Cu2+(aq) Au(s) + Cu2+(aq) → Au3+(aq) + Cu+(aq) Au3+(
Rasek [7]

Answer:

Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq)

1.35 V

Explanation:

Given that the reduction potential of

Cu^2+(aq) + e- -----> Cu^+(aq) is +0.15 V

While the reduction potential of

Au3+(aq) + 3 e- -----> Au(s) is + 1.50V

It is clear that the Cu^+(aq)/Cu^2+(aq) system is the anode while Au^3+(aq)/Au(s) system is the cathode based on the reduction potentials shown above. The number of electrons transferred (n) =3

E°cell = E°cathode - E°anode

E°cell= 1.50-0.15

E°cell= 1.35 V

3 0
3 years ago
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