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timama [110]
3 years ago
5

A Se ion has a mass number of 76 and a charge of − 2 . Determine the number of neutrons, protons, and electrons in this ion.

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
8 0

Answer:

Neutron = 42

Proton = 34

Electron = 36

Explanation:

The atomic number (also known as the proton number) of an element does not change even if the element gain or loss electrons.

With this understanding,

Se has atomic number(proton number) = 34

From question,

Mass number of Se ion = 76

Charge = - 2

Neutron number = Mass number - proton number

Neutron number = 76 - 34 = 42

Since Se ion has a charge of 2-, it means it has gain electrons

Therefore the electron number = 34 + 2 = 36

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Vera_Pavlovna [14]

Answer:

<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>

Explanation:

No. of moles = \frac{mass}{molar mass}

= \frac{0.254}{204} = 0.001245 moles

Concentration of KHP (C1) in litres = n/v

= \frac{0.001245}{0.02} = 0.062 mol/L

We know that:

C_{1} V_{1} = C_{2} V_{2}

where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.

Since mole ratio is 1 : 1.

1 mole of NaOH - 40g

0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g

⇒0.0498g of NaOH was used during the titration

<u><em>∴Mass concentration (g/L) = 0.0498g ÷ 0.02L</em></u>

<u><em>= 2.49g/L.</em></u>

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3 years ago
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Explanation:

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1. How many calcium atoms are in 8CaOH?
Vedmedyk [2.9K]

Answer:

8

Explanation:

the number before the abbrviation for calcium (Ca) shows how many calcium there is.

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If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres, what is the volume of the gas?
iVinArrow [24]

If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres the volume of the gas 1.66 litres.

Explanation:

Data given:

number of moles of the gas = 0.725

temperature = 105 K

pressure = 3.75 atm

volume of the gas =?

R = 0.08206 Latm/mole Kelvin

Applying the ideal gas law to calculate the volume of the given gas:

PV = nRT

rearranging the equation to calculate volume:

V = \frac{nRT}{P}

putting the values in the equation:

V = \frac{0.08206 X 0.725 X 105}{3.75}

V = 1.66 Litres.

At a temperature of 105 K and pressure of 3.75 atm, 0.725 moles of gas occupy 1.66 litres of volume.

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