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3 years ago

Which best describes the relationship between population size, carrying capacity, and limiting factors?

Physics

2 answers:

borishaifa [10]3 years ago

7 0

Answer:

is b

Explanation:

Alexandra [31]3 years ago

6 0

When the sources is not enough for a population size that would limit population growth are limiting factors. And these limiting factors prevent the population size to increase. When it stops growing, the ecosystem reaches its carrying capacity. <span>Carrying capacity is the end of the line of a population size that the ecosystem can support over time.</span>

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There are five basic health-related components that one must have in order to be physically fit.

kirza4 [7]

Answer: the answer is true :-)

Explanation:

7 0

3 years ago

A cannon fires a 0.2 kg shell with initial velocity vi = 9.2 m/s in the direction θ = 46 ◦ above the horizontal. The shell’s tra

Sedbober [7]

Answer:

∆h = 0.071 m

Explanation:

I rename angle (θ) = angle(α)

First we are going to write two important equations to solve this problem :

Vy(t) and y(t)

We start by decomposing the speed in the direction ''y''

$sin(\alpha) = \frac{Vyi}{Vi}$

$Vyi = Vi.sin(\alpha ) = 9.2 \frac{m}{s} .sin(46) = 6.62 \frac{m}{s}$

Vy in this problem will follow this equation =

$Vy(t) = Vyi -g.t$

where g is the gravity acceleration

$Vy(t) = Vyi - g.t= 6.62 \frac{m}{s} - (9.8\frac{m}{s^{2} }) .t$

This is equation (1)

For Y(t) :

$Y(t)=Yi+Vyi.t-\frac{g.t^{2} }{2}$

We suppose yi = 0

$Y(t) = Yi +Vyi.t-\frac{g.t^{2} }{2} = 6.62 \frac{m}{s} .t- 4.9\frac{m}{s^{2} } .t^{2}$

This is equation (2)

We need the time in which Vy = 0 m/s so we use (1)

$Vy (t) = 0\\0=6.62 \frac{m}{s} - 9.8 \frac{m}{s^{2} } .t\\t= 0.675 s$

So in t = 0.675 s → Vy = 0. Now we calculate the y in which this happen using (2)

$Y(0.675s) = 6.62\frac{m}{s}.(0.675s)-4.9 \frac{m}{s^{2} } .(0.675s)^{2} \\Y(0.675s) =2.236 m$

2.236 m is the maximum height from the shell (in which Vy=0 m/s)

Let's calculate now the height for t = 0.555 s

$Y(0.555s)= 6.62 \frac{m}{s} .(0.555s)-4.9\frac{m}{s^{2} } .(0.555s)^{2} \\Y(0.555s) = 2.165m$

The height asked is

∆h = 2.236 m - 2.165 m = 0.071 m

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4 years ago

What condition is required for cloud formation in the atmosphere?

Vedmedyk [2.9K]

Answer: To form a cloud, the air that rises must cool to the point where some of the water vapor molecules "clump together" at a faster pace than they are pulled apart by their thermal energy. These molecules then condense to form the clouds and water droplets.

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4 years ago

This property of matter describes<br> the relationship of mass to volume?

DedPeter [7]

Density is a physical property that describes the relationship between mass and volume. Density is the amount of matter in a given space, or volume.

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2 years ago

. A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is

zysi [14]

V^2 = u^2 + 2gr, where v - speed, u - initial speed=0, r - displacement (or height)
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4 0

3 years ago

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