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vovangra [49]
2 years ago
15

What is the quotient and remainder of 27÷2

Mathematics
2 answers:
Tems11 [23]2 years ago
8 0

Answer:

13 with a remander of 1

Step-by-step explanation:

AfilCa [17]2 years ago
6 0
13 with a remainder of 1
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Jessie painted a rectangular wall that measured 7 yards by 3 yards.
Lunna [17]

Answer:

Im gonna have to say 21 yd^2.

Step-by-step explanation:

L*W=A^2 so... 7*3=21

7 0
3 years ago
Read 2 more answers
Can you pls help me with this question thank you
Murljashka [212]

How can expressions be written and evaluated to solve for unknowns in the real world?

Writing expressions requires figuring out which quantity in a situation is unknown, and define a variable to represent that quantitiy.

We look for words in the problem that will help us out what kind of operation to use in a given situation.

Example:

Donna bought 5 chocolate bars, and then ate some. Write an expression to represent how many chocolate bars Donna has left.

If we let the variable c represent the number of chocolates Donna has eaten, then we can write the expression on how many bars Donna has left as: 5 - c

3 0
11 months ago
The sum of the digits of a 5 digit positive integer =2 how many five digits integers exist?
yaroslaw [1]
Answer- 90000/2=45000

5 0
2 years ago
Rhonda has $4.85 in coins. If she has six more nickels than dimes and twice as many quarters as dimes, how many coins of each ty
Novay_Z [31]

Answer: nickels = 13, dimes = 7, quarters = 14

<u>Step-by-step explanation:</u>

First, set up the equations for each coin:

\begin {array}{c|c|c|l}\underline{\quad Type\quad }&\underline{Value}&\underline{Quantity}&\underline{\qquad \qquad \qquad Equation\qquad }\\ Nickel& \$0.05&6+d&0.05(6+d) = 0.30 + 0.05d\\Dime& \$0.10&d&\qquad 0.10(d)=0.10d\\Quarter& \$0.25&2d&\qquad 0.25(2d)=0.50d\\\end{array}

Next, the sum of the coins is $4.85 so substitute and solve for the variable:

   Nickels         +   Dimes  +   Quarters = Sum

(0.30 + 0.05d)  +    0.10d   +     0.50d   =  4.85

0.30 + 0.65d = 4.85

            0.65d = 4.55

                    d = 7

Lastly, plug the d-value into the quantity equation for the nickels and quarters to find their quantity.

nickels: 6 + d   = 6 + (7)   = 13

quarters: 2d   = 2(7)   = 14

6 0
2 years ago
Find the product of monomials<br> 3a^4b^-2 and 2a^7b^-1
Inga [223]
(3a^4 * b^-2) * (2a^7 * b^-1)
= 6*a^(4+7)*b^(-2-1)
= 6*a^11*b^-3
5 0
2 years ago
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