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-Dominant- [34]
3 years ago
7

Given m||n, find the value of x and y

Mathematics
1 answer:
34kurt3 years ago
4 0
<h2>Answer: </h2><h3> x=15 & y=52</h3>

Hope this might help you (•.•) :)

You might be interested in
one bag of toy animals weigh12 ounces. what is the total weight, in ounces, of the bags of toy animals in one crate
LUCKY_DIMON [66]
Assuming I understand what you're saying, if there are 2 boxes in a crate and 18 bags in a box, the answer would be 12 * 36 = 432
6 0
4 years ago
Please I need help I’m being timed.please
Sindrei [870]

Answer:

C, D, and E

Step-by-step explanation:

85-20=65

t>65

This means all the numbers greater than 65.

Do not include 65 because it is not a greater than or equal to symbol.

Hope this helps!

If not, I am sorry.

8 0
2 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
Please help, I’m very confused
snow_tiger [21]

Answer:

1st picture: (0,4)

The lines intersect at point (0,4).

2nd picture: Graph D

2x ≥ y - 1

2x - 5y ≤ 10

Set these inequalities up in standard form.

y ≤ 2x + 1

-5y ≤ 10 - 2x → y ≥ -2 + 2/5x → y ≥ 2/5x - 2

When you divide by a negative number, you switch the inequality sign.

Now you have:

y ≤ 2x + 1

y ≥ 2/5x - 2

Looking at the graphs, you first want to find the lines that intersect the y-axis at (0, 1) and (0, -2).

In this case, it is all of them.

Next, you would look at the shaded regions.

The first inequality says the values are less than or equal to. So you look for a shaded region below a line. The second inequality says the values are greater than or equal to. So you look for a shaded region above a line.

That would mean Graph B or D.

Then you look at the specific lines. You can see that the lower line is y ≥ 2/5x - 2. You need a shaded region above this line. You can see the above line is y ≤ 2x + 1. You need a shaded region below this line. That is Graph D.

8 0
3 years ago
Read 2 more answers
Please help me find
erica [24]

Answer:

150 feet

Step-by-step explanation:

the ratio of her shadow to her height

2/5=60/150

60/150=2/5

i hope it is right

3 0
3 years ago
Read 2 more answers
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