In ΔTUV, the measure of ∠V=90°, the measure of ∠T=55°, and VT = 56 feet. Find the length of TU to the nearest tenth of a foot.
2 answers:
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Answer:
149.30ft
Step-by-step explanation:
Since the vertical distance between the two tower = 40ft
The angle of elevation from the lower tower to te higher tower = 15°
The horizontal distance between the two towers = x
Assuming the angle of elevation and the distance between the two towers makes a right angle triangle, we can use SOHCAHTOA and determine which one would be suitable to find x.
Check attached document for better illustration of the triangle.
Tanθ = opposite / adjacent
Opposite = 40
θ = 15°
Adjacent = x
Tan15 = 40 / x
0.2679 = 40 / x
X = 40 / 0.2679
X = 149.30ft
The horizontal distance between the two towers is 149.30ft
The salary of the real estate broker = $18,000
Commission earned on total sales = 4% or 0.04
Total income earnings = $55,000
Let the total sales be = x
Equation becomes :
Hence, the real estate broker must sell $925,000 worth of real estate to earn $55,000.