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azamat
3 years ago
10

The electrician charges $50 per visit plus $12 per hour of work. Steve hires the electrician to do some work for his house. If S

teve's budget is $200, how many hours could the electrician work?
12.5 hours
22 hours
11 hours
Mathematics
1 answer:
TEA [102]3 years ago
8 0

Answer:

12.5 hours

Step-by-step explanation:

budget: 200

fix cost: 50

hourly rate: 12

hours: ?

----

First we deduct the fix 50 dollars cost from the total budget.

Then we divide the remaining amount with the hourly rate

( 200 - 50 ) / 12 = ?

? = 12.5 hours

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OverLord2011 [107]

Answer:

D. 4x-13=1

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2 years ago
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Ne4ueva [31]

Answer:

B. 2 3/4 lbs

Step-by-step explanation:

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2 years ago
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1.Give one number that makes the inequality x + 7 &gt; 20 true
nata0808 [166]
1. Any number above 13 works. Why? Because 20-7=13, and to be greater than 20, you must add a number larger than 13.

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2. Any number below 25/3 (which is also 8.3 with a repeating 3) works. Why? Because 25/3=8.3 with a repeating 3, and to remain less than 25, you must multiply by a number less than 8.3 with a repeating 3.

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3. 4 buses. 1 bus will hold 60 students, 2 will hold 120, 3 will hold 180, and 4 will hold 240. The question is trying to trick you into putting now 3.3333333333... buses because that's what 200/60 is, but there is no such thing as a third of a bus. So you need at least 4 buses. (There will be an extra 40 spaces for passengers on the 4th bus, but that is okay.)

To find this answer I did 200/60 and got 3.3 with a repeating 3. You must round to the higher whole number. Rounding down to 3 buses leaves you with 20 students without a bus.

4. 19 boxes. 18 boxes will only hold 288 candies. The question is trying to trick you into putting down 18.75 boxes because that's what 300/16 is, but there is no such thing as 75% of a box. So you need at least 19 boxes. (There will be an extra 4 spaces for candies in the 19th box, but that is okay.)

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6 0
3 years ago
Use the Laplace transform to solve the given initial value problem. y' + 6y = e^4t ; y(0)=2 ...?
TiliK225 [7]
Performing laplace transform of the equation.

sY(s) - y(0) + 6Y(s) = 1/(s-4)
(s+6)Y(s) - 2 = 1/(s-4)
Y(s) = 2/(s+6) + 1/(s-4)(s+6), by partial fraction decomposition
Y(s) = 2/(s+6) + 1/10 * (1/(s-4) + 1/(s+6))
Y(s) = 0.1/(s-4) + 2.1/(s+6)

Performing inverse laplace transform,
y(t) = 0.1e^4t + 2.1e^(-6t)


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
What is the greatest common factor of 6d² and 18d<br><br>​
VMariaS [17]

gcd  =  6  ⋅  d

Step-by-step explanation:

We have that  

6 d ^2  =  6  ⋅  d  ⋅  d and  18 d  =  3  ⋅  6  ⋅  d  hence the  gcd  =  6  ⋅  d

(Hope this helps <3)

3 0
2 years ago
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