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3 years ago

4 1/8 take away 1 1/2

Mathematics

2 answers:

amm18123 years ago

5 0

Answer:

2 5/8

Step-by-step explanation:

Lana71 [14]3 years ago

3 0

I think it’s 2 5/8 but I’m not sure!

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6 + 5/9 what is the answer

svetoff [14.1K]

Answer:

6.5 i think im not smart

Step-by-step explanation:

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3 years ago

What’s the slope of the line??

emmainna [20.7K]

If I did the math correctly I’d should be -5 or rewritten as -5/1.

8 0

3 years ago

If the domain of the square root function f(x) is x less-than-or-equal-to 7, which statement must be true?

Damm [24]

Answer:

The x-term inside the radical has a negative coefficient.

Step-by-step explanation:

hope this helps

3 0

3 years ago

Read 2 more answers

a pile of sand has a weight of 90kg The sand is put into a small bag, a medium bag and a large bag in the ratio of 2 : 3 : 7 Wor

just olya [345]

Hi there!

To split 90 kilos in the ratio of 2 : 3 : 7 we must first realise that we have a total of 2 + 3 + 7 = 12 parts, in which we must split the total 90 kilos.

12 parts equal 90 kilo, and therefore
1 part equals 90 / 12 = 7.5 kilos.

1 part equals 90 / 12 = 7.5 kilos, and therefore
2 parts equal 7.5 × 2 = 15 kilos.

1 part equals 90 / 12 = 7.5 kilos, and therefore
3 parts equal 7.5 × 3 = 22.5 kilos.

1 part equals 90 / 12 = 7.5 kilos, and therefore
7 parts equal 7.5 × 7 = 52.5 kilos.

Hence, 90 kilos in the ratio of 2 : 3 : 7
gives 15 kg, 22.5 kg and 52.5 kg.

~ Hope this helps you!

3 0

3 years ago

For fun question

ZanzabumX [31]

Consider the function $f(x)=x^{1/3}$ , which has derivative $f'(x)=\dfrac13x^{-2/3}$ .

The linear approximation of $f(x)$ for some value $x$ within a neighborhood of $x=c$ is given by

$f(x)\approx f'(c)(x-c)+f(c)$

Let $c=64$ . Then $(63.97)^{1/3}$ can be estimated to be

$f(63.97)\approxf'(64)(63.97-64)+f(64)$
$\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375$

Since $f'(x)>0$ for $x>0$ , it follows that $f(x)$ must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function $f(x)$ . This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...

4 0

3 years ago