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kirill115 [55]
3 years ago
13

You apply a force of 19 lbs on to the end of a lever to lift a crate. The resistance of the load is 106 lbs. Calculate the

Engineering
1 answer:
zhuklara [117]3 years ago
3 0
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Explain with schematics the operating principle of solid state lasers.
alina1380 [7]

Explanation:

A solid state laser contains a cavity like structure fitted with spherical mirrors or plane mirrors at the end filled with a rigidly bonded crystal. It uses solid as the medium. It uses glass or crystalline materials.

    It is known that active medium used for this type of laser is a solid material. This lasers are pumped optically by means of a light source which is used as a source of energy for the laser. The solid materials gets excited by absorbing energy in the form of light from the light source. Here the pumping source is light energy.  

7 0
3 years ago
Cos square there + cos square theta multiply cot square theta = cot square theta​
Ivahew [28]

Explanation:

We need to prove that : \cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta=\cot^2\theta

Taking LHS : \cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta

Taking \cos^2\theta common as follows :

\cos^2\theta(1+ \cot^2\theta) ...(1)

We know that :

cosec^2\theta-\cot^2\theta=1\\\\cosec^2\theta=1+\cos^2\theta ....(2)

Use equation (2) in equation (1) as follows :

\cos^2\theta{\cdot} cosec^2\theta

We know that : cosec\theta=\dfrac{1}{\sin\theta}

So,

\cos^2\theta{\cdot} \dfrac{1}{\sin^2\theta}\\\\=\cot^2\theta

=RHS

Hence, LHS = RHS

8 0
3 years ago
The shaft is hollow from A to B and solid from B to C. The shaft has an outer diameter of 79 mm, and the thickness of the wall o
SVETLANKA909090 [29]

Answer:

<u><em>Maximum Shear Stress is 62.0 MPA </em></u>

Explanation:

<h2><u /></h2><h3><u>Please refer to the attachment below for explanation.</u></h3>

7 0
4 years ago
What is the moment that the wrench puts on the bolt?
Natalka [10]

Answer:

Suppose we have a 6-foot board with a 10-pound bag of flour on it. If we put a pivot under

the board, the flour will create a torque on the board. Torque is like force, but it tends to

rotate things instead of moving them in a straight line. The torque generated by the flour is

T = r × F

where F is the force that gravity exerts on the flour (i.e., 10 lb), and r is the distance from

the pivot to the bag. So if the pivot is in the middle of the board (x = 3 ft) and the flour is

a foot to the right (x = 4 ft) then the torque is

(4 ft − 3 ft) × 10 lb = 10 ft·lb.

The greater a torque is, the more the board will tend to rotate. This explains how a wrench

works: you put a long wrench on a stuck bolt and push, and you generate a torque which

is greater (because of the length of the wrench) than if you just tried to turn the bolt with

your hand.

The board above will tend to rotate clockwise. If, instead of the flour on the right, we put

a 10 pound block of ice to the left of the pivot at x = 2, like this:

2

10

0 6

then the board will tend to rotate counterclockwise. To keep the two cases straight, we’ll

say that the flour was generating a torque of +10 ft·lb and the ice is generating a torque of

−10 ft·lb. Positive torque means clockwise, negative means counterclockwise. We can keep

our simple formula “T = r × F” by making r negative when the weight is to the left of the

pivot and positive when it’s to the right. That’s what we get when we set

r = (x-position of weight) − (x-position of pivot).

Having signed torques is convenient, because if we have both the flour and ice on the board,

2

10

4

10

Explanation:

6 0
3 years ago
A venture tube is used to measure the flow rate of a liquid in a pipe (liquid density is 800 kg/m3). The pipe has a diameter of
UNO [17]

Answer:

\triangle h=4.935m

Explanation:

From the question we are told that:

Liquid density \rho=800

Diameter of pipe d=4cm \approx 0.004m

Diameter of venture d=10cm \approx 0.010m

Specific weight of mercury P_mg 133 kN/m^3

Flow rate r=0.05 m^3/s

Area A:

            A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\

Generally the Bernoulli's equation is mathematically given by

\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\

Where

V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}

Therefore

P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})

Generally the equation for pressure difference b/w manometer fluid is given as

P_1-P_2=(p_mg-pg)\triangle h

Therefore

(p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})

\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}

\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}

\triangle h=4.935m

Therefore elevation change is mathematically given by

\triangle h=4.935m

5 0
3 years ago
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