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Answer:
The answer to your question is: Molarity = 0.078
Explanation:
Data
HCl
V = 250 ml
T = 27°C = 300 °K
P = 141 mmHg = 0.185 atm
V2 = 70 ml
NaOH
V = 24.3 ml
Molarity NaOH = ?
Process
1.- Calculate the number of moles of HCl
PV = nRT
n = PV / RT
R = 0.082 atm l / mol K
n = (0.185)(0.25) / (0.082)(300)
n = 0.046 / 24.6
n = 0.0019 moles
2.- Calculate molarity of HCl
Molarity = moles / volume
Molarity = 0.0019 / 0.070
Molarity = 0.027
3.- Write the balanced equation
HCl + NaOH ⇒ H₂O + NaCl
Here, we observe that the proportion HCl to NaOH is 1:1 .
Then 0.0019 moles of HCl reacts with 0.0019 moles of NaOH.
4.- Calculate the molarity of NaOH.
Molarity = 0.0019 / 0.0243
Molarity = 0.078
A mole of any element is equal to avogadro's number which is equivalent to 6.0221409e+23, that is 6.0221409e+23 molecules or atoms per mole.In this case, we are given with 9.87 sample which when multiplied to Avogadro's number is equal to <span>5.943853e+24 atoms.</span>
The reactants and products involved in the chemical reaction are written on the left and right hand side of the equation, respectively. Thus, the reactants are SO3(g) and H2O(l). The product is H2SO4(aq). This reaction is an example of synthesis wherein two reactant combine to form one product.